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Llana [10]
3 years ago
6

In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.2. What is the

frequency of individuals with Aa genotype? will reward brainly for best answer with explanation...please no more links or i will report
Biology
1 answer:
kolezko [41]3 years ago
4 0

Answer:

0.42

Explanation:

<em> To estimate the frequency of alleles in a population, we can use the  </em>

<em>According to this equation:- </em>

<em>p =  </em>

<em>q =  </em>

<em> </em>

<em>p + q = 1.0  </em>

<em>(p + q)  </em>

<em>2 </em>

<em>  = 1 so p  </em>

<em>2 </em>

<em>  + 2pq + q  </em>

<em>2 </em>

<em>  = 1 </em>

<em> </em>

<em>p  </em>

<em>2 </em>

<em>   </em>

<em>2pq = frequency of Aa  </em>

<em>q  </em>

<em>2 </em>

<em> </em>

<em>p+q = 1 </em>

<em>0.3 + q = 1 </em>

<em>q = 1 - 0.3 = 0.7 </em>

<em>Aa = 2pq = 2* 0.3 * 0.7 = 0.42. </em>

<em> </em>

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