In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.2. What is the
frequency of individuals with Aa genotype? will reward brainly for best answer with explanation...please no more links or i will report
1 answer:
Answer:
0.42
Explanation:
<em>
To estimate the frequency of alleles in a population, we can use the </em>
<em>According to this equation:-
</em>
<em>p = </em>
<em>q = </em>
<em>
</em>
<em>p + q = 1.0 </em>
<em>(p + q) </em>
<em>2
</em>
<em> = 1 so p </em>
<em>2
</em>
<em> + 2pq + q </em>
<em>2
</em>
<em> = 1
</em>
<em>
</em>
<em>p </em>
<em>2
</em>
<em>
</em>
<em>2pq = frequency of Aa </em>
<em>q </em>
<em>2
</em>
<em>
</em>
<em>p+q = 1
</em>
<em>0.3 + q = 1
</em>
<em>q = 1 - 0.3 = 0.7
</em>
<em>Aa = 2pq = 2* 0.3 * 0.7 = 0.42.
</em>
<em>
</em>
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