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julia-pushkina [17]

2 years ago

14

In a science experiment an independent variable is

1 answer:

kvasek [131]2 years ago

6 0

A variable that remains unchanged throughout the experiment.

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In a computer game, a bird flies at a height of 1,281 feet. At the same time, a fish swims 282 feet below sea level. What is the

fenix001 [56]

To find the difference, we need to subtract the height of the fish from the height of the bird. If we use sea level as 0, then the bird flies at 1,281 feet, and the fish swims at -282 feet.

1,281 - (-282) = <span>1,281 + 282 = 1,563 feet

There is a </span><span>1,563 feet difference between the height of the bird and the depth of the fish</span>

6 0

2 years ago

Read 2 more answers

A school band gives a year-end concert. It is held in a 400-seat auditorium. Each concert ticket sells for $10, and 85% of the t

bazaltina [42]

Answer: $3,400

Step-by-step explanation:

There are 400 seats in the auditorium which means that there are 400 tickets to be sold.

85% of these tickets are sold. The number of tickets sold is:

= 85% * 400

= 340 tickets were sold.

Each ticket sells for a total of $10.

The amount of money made from ticket sales is therefore:

= No. of tickets sold * price of ticket

= 340 * 10

= $3,400

6 0

2 years ago

10 points pls answer this is due tonight

lilavasa [31]

1.12 2.60 hope this helps if it is wrong then I’m sorry

5 0

2 years ago

Which function does not have a vertical asymptote

Gemiola [76]

Answer:

$y=\frac{5x}{1+2x^2}$

Step-by-step explanation:

$Option ~A ~ does ~ not ~ have ~a ~ vertical~ asymptote$

<u>--------------------------</u>

Hope it helps...

Have a great day!!

8 0

2 years ago

If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c

dolphi86 [110]

Given:

$(ax+2)(bx+7)=15x^2+cx+14$

And

$a+b=8$

Required:

To find the two possible values of c.

Explanation:

Consider

$\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}$

So

$\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}$

And also given

$a+b=8---(2)$

Now from (1) and (2), we get

$\begin{gathered} a+\frac{15}{a}=8 \\ \\ a^2+15=8a \\ \\ a^2-8a+15=0 \end{gathered}$ $a=3,5$

Now put a in (1) we get

$\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}$

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

$\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}$

When a=5 and b=3, we have

$\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}$

Final Answer:

The option D is correct.

31 and 41

8 0

5 months ago