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aliina [53]
3 years ago
11

A fair six-sided dice is rolled once. What is the probability that a 2 is shown?

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
8 0
Answer:
1/6

Explanation:
It would be 1/6 because the fair is six-sided and the denominator is always how much of it is.
VashaNatasha [74]3 years ago
3 0

Answer:

C: 1/6

Step-by-step explanation:

There is one 2 on a six sided die. Therefore there is a 1/6 chance that it was a 2.

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The highway department is testing two types of reflecting paint for concrete bridge end pillars. The two kinds of paint are alik
tankabanditka [31]

Answer:

a. difference of means

Step-by-step explanation:

Given that :

Mean , x = 9.4

Standard deviation, s.d_1 = 2.5

Number, n_1 = 12

Mean, y = 6.5

standard deviation, s.d_2 = 2.4

Number, n_2 = 12

The null hypothesis is : $H_0: \mu_1=\mu_2$

The alternate hypothesis is : $H_1: \mu_1>\mu_2$

Level of significance, \alpha = 0.1

From the \text{standard normal table, right tailed,} $t_{1/2}$ = 1.363

Since out test is right tailed.

Reject H_0, if $T_0>1.363$

We use the test statics,

$t_0=\frac{(x-y)}{\sqrt{\frac{s.d_1}{n_1}+\frac{s.d_2}{n_2}}}$

$t_0=\frac{(9.4-6.5)}{\sqrt{\frac{6.25}{12}+\frac{5.76}{12}}}$

$t_0=2.899$

$|t_0|=2.899$

\text{Critical value}

The value of $|t_{1/2}|$ with minimum $\left(n_1-1,n_2-1)$ that is 11 df is 1.363

We go $|t_0|=2.899$ and $|t_{1/2}|$ = 1.363

Decision making:

Since the value of |t_0|>|t_{1/2}|$  and we reject the H_0

The p-value : right tail H_a:(p>2.8988)

                                      = 0.00724

Therefore the value of $p_{0.1} > 0.00724$, and so we reject the H_0

Thus we are testing 'the difference of means" in this problem.

7 0
3 years ago
Find the unknown digit to make each statement true
notsponge [240]
Whats the equation to the question

7 0
3 years ago
Solve system by elimination<br> y=x^2<br> y=x+2<br> SHOW YOUR WORK
Dimas [21]
We have that
y=x²----> equation 1<span>
y=x+2-----> equation 2

multiply equation 1 by -1
-y=-x</span>²

add equation 1 and equation 2
-y=-x²
 y=x+2
------------
0=-x²+x+2-------------> -x²+x+2=0-----> x²-x-2=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x²-x)=2
<span>Complete the square. Remember to balance the equation by adding the same constants to each side
</span>(x²-x+0.5²)=2+0.5²

Rewrite as perfect squares

(x-0.5)²=2+0.5²
(x-0.5)²=2.25-----> (x-0.5)=(+/-)√2.25-----> (x-0.5)=(+/-)1.5
x1=1.5+0.5-----> x1=2
x2=-1.5+0.5---- > x2=-1

for x=2
y=x²----> y=2²----> y=4
the point is (2,4)

for x=-1
y=x²----> y=(-1)²---> y=1
the point is (-1,1)

the answer is
the solution of the system are the points
(2,4) and (-1,1)


3 0
4 years ago
Watch student agreed to sell at least 50 seed packages for a school project. Yesterday one student sold 22 packages, and today t
11111nata11111 [884]

Answer:

Student a is 28

Student b is 33

5 0
3 years ago
What is the value of x in the figure shown below
gayaneshka [121]

Answer:

x = 34 degrees

Step-by-step explanation:

if this is a parallelogram then Δ ACB ≅ Δ DCB

which means that ∠A = ∠D

7 0
3 years ago
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