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Dima020 [189]
3 years ago
11

Write the expanded form for this expression -1/2(y - x)

Mathematics
1 answer:
grin007 [14]3 years ago
5 0

Answer:  =-1/2x+-1/2y

Step-by-step explanation:

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A student creates a table of the equation y = 5x + 8. The student begins the table as shown below. Which shows the correct headi
SVEN [57.7K]

Answer:

1

Step-by-step explanation:

Column A=X the first value for x is 1

Column B has the x value replaced in the equation 5x+8. 5(1) + 8

Column C has the result, y=13

3 0
3 years ago
Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .
kogti [31]

Answer:

The family of all prime numbers such that a^{2} + b^{2} + c^{2} -1 is a perfect square is represented by the following solution:

a is an arbitrary prime number. (1)

b = \sqrt{1 + 2\cdot a \cdot c} (2)

c is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if (x+y)^{2} = x^{2} + 2\cdot x\cdot y  + y^{2}. From statement, we must fulfill the following identity:

a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}

By Associative and Commutative properties, we can reorganize the expression as follows:

a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2} (1)

Then, we have the following system of equations:

x = a (2)

(b^{2}-1) = 2\cdot x\cdot y (3)

y = c (4)

By (2) and (4) in (3), we have the following expression:

(b^{2} - 1) = 2\cdot a \cdot c

b^{2} = 1 + 2\cdot a \cdot c

b = \sqrt{1 + 2\cdot a\cdot c}

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, a, b, c > 1. If a, b and c are prime numbers, then  2\cdot a\cdot c must be an even composite number, which means that a and c can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.

In addition, b must be a natural number, which means that:

1 + 2\cdot a\cdot c \ge 4

2\cdot a \cdot c \ge 3

a\cdot c \ge \frac{3}{2}

But the lowest possible product made by two prime numbers is 2^{2} = 4. Hence, a\cdot c \ge 4.

The family of all prime numbers such that a^{2} + b^{2} + c^{2} -1 is a perfect square is represented by the following solution:

a is an arbitrary prime number. (1)

b = \sqrt{1 + 2\cdot a \cdot c} (2)

c is another arbitrary prime number. (3)

Example: a = 2, c = 2

b = \sqrt{1 + 2\cdot (2)\cdot (2)}

b = 3

4 0
3 years ago
Here's the question: You have an electrical circuit with various components, all of which are in series. The current (I) through
vredina [299]

Answer:Magnitude of voltage is 41.9963 volts


Step-by-step explanation:

Given that current I =5.772-5.323i mA

          and impedance, Z=3.342+4.176i kilo ohms

Then voltage in the circuit = IZ

                                            =(5.772-5.323i)X10^{-3}X(3.342+4.176i)X10^{3}

                                      V=(5.772-5.323i)X(3.342+4.176i)

                                      V=19.290024+24.103872i-17.789466i-23..5148848i^{2}

                                     V=41.518892+6.314406i

Magnitude of V = \sqrt{41.518892^{2} +6.314406^{2} }=\sqrt{1763.6901}=41.9963volts


7 0
3 years ago
Which two numbers have a sum of 11 and product of 28?​
Elanso [62]
7 and 4

7+4=11
7•4=28

Hope it helps
7 0
3 years ago
Solve 12−5x−4kx=y for x.
IgorC [24]

Answer:

x = \frac{12-y}{4k+5}

Step-by-step explanation:

12-5x-4kx=y

1. Subtract 12 from both sides.

2.Distrubutive property (factor) a(b+c)=ab+ac

x(-5-4k)=y-12

  • Divide by -5-4k

x = \frac{y-12}{-5-4k}

= \frac{12-y}{4k+5}

5 0
3 years ago
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