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satela [25.4K]
2 years ago
12

Carey is trying to decide between two guitars. The first had an original price of $160, but is on sale for $100. The second had

an original price of $250, but is on sale for $150. Which guitar has a greater percent change in price? The first guitar has greater percent change of approximately 35%. The second guitar has a greater percent change of approximately 40%. The first guitar has a greater percent change of approximately 54%. The second guitar has a greater percent change of approximately 67%.
Mathematics
2 answers:
MissTica2 years ago
7 0

Answer:

40%

Step-by-step explanation:

Zolol [24]2 years ago
3 0

Subtract the sale price from the original price then divide the difference by the original price.

Guitar 1: 160 -100 = 60

60/160 = 0.375 x 100 = 37.5%

Guitar 2: 250 - 150 = 100

100/250 = 0.4 x 100 = 40%

The answer is the second guitar has a greater percent change of approximately 40%

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Consider the points A(5, 3t+2, 2), B(1, 3t, 2), and C(1, 4t, 3). Find the angle ∠ABC given that the dot product of the vectors B
Vilka [71]

Answer:

66.42°

Step-by-step explanation:

<u>Given:</u>

A(5, 3t+2, 2)

B(1, 3t, 2)

C(1, 4t, 3)

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Step 1: Find t.

First we have to find vectors BA and BC. We do that by subtracting the coordinates of the initial point from the coordinates of the terminal point.

In vector BA B is the initial point and A is the terminal point.

BA = OA - OB = (5-1, 3t+2-3t, 2-2) = (4, 2, 0)

BC = OC - OB = (1-1, 4t-3t, 3-2) = (0, t, 1)

Now we can find t because we know that BA • BC = 4

BA • BC = 4

To find dot product we calculate the sum of the produts of the corresponding components.

BA • BC = (4)(0) + (2)(t) + (0)(1)

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2 = t

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Now we know that:

BA = (4, 2, 0)

BC = (0, 2, 1)

Step 2: Find the angle ∠ABC.

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BA • BC = 4

|BA| |BC| cos(angle) = 4

To get magnitudes we square each compoment of the vector and sum them together. Then square root.

|BA| = \sqrt{4^2 + 2^2 + 0^2} = \sqrt{20} = 2\sqrt{5}

|BC| = \sqrt{0^2 + 2^2 + 1^2} = \sqrt{5}

2\sqrt{5}\sqrt{5}\cos{(m\angle{ABC})} = 4

10\cos{(m\angle{ABC})} = 4

\cos(m\angle{ABC}) = \frac{4}{10}=\frac{2}{5}

m\angle{ABC} = cos^{-1}{(\frac{2}{5})}

m\angle{ABC} = 66.4218^{\circ}

Rounded to two decimal places:

m\angle{ABC} = 66.42^\circ

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