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gayaneshka [121]
3 years ago
6

Which figures are polygons? Figure A has 6 sides all made of line segments. figure b is a regular hexagon. it has 6 sides made a

ll of segments. Figure c is shaped iike a long semicircle. the bottom is a segment. The top part is curved. Figure D has 7 sides which are all segments.
Mathematics
2 answers:
Kryger [21]3 years ago
7 0

Answer:

D

Step-by-step explanation:

Naddika [18.5K]3 years ago
4 0
<span>A polygon is a closed figure made by joining line segments, where each line segment intersect exactry two other line segments.

A polygon is said to be a regular polygon if the sides are all of the same length.

Thus, the figures that are polygon are:

</span><span>Figure A which has 6 sides all made of line segments.

Figure B which is a regular hexagon, having 6 sides made all of segments.

</span><span>Figure D has 7 sides which are all segments.</span>
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How do you do this???
densk [106]

Answer:

Step-by-step explanation:

∠ E  =∠ B    { corresponding part of congruence triangle are equal}

2x + 4 = 40

2x = 40 - 4

2x = 36

x = 36/2

x = 18

7 0
3 years ago
shawn works 40 hours a week as a store manager. if he made $27,040 last year, how much was he paid per hour?
kicyunya [14]
Just divide 27.040 divided by 40 equals 0.648 witch means 648 $ per hour well i think
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3 years ago
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A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second. The function h(t)=−16t2+55t+4
kramer

<u>Given</u>:

A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second.

The function h(t)=-16t^2+55t+4 represents the height h(in feet) of the ball after t seconds.

We need to determine the time of the ball at which it is 30 feet above the ground.

<u>Time:</u>

To determine the time that it takes for the ball to reach a height of 30 feet above the ground, let us substitute h(t) = 30, we get;

30=-16t^2+55t+4

26=-16t^2+55t

Adding both sides of the equation by 16t², we get;

16t^2+26=55t

Subtracting both sides of the equation by 55t, we have;

16t^2-55t+26=0

Let us solve the quadratic equation using the quadratic formula, we get;

t=\frac{-(-55) \pm \sqrt{(-55)^2-4(16)(26)}}{2(16)}

t=\frac{55 \pm \sqrt{3025-1664}}{32}

t=\frac{55 \pm \sqrt{1361}}{32}

t=\frac{55 \pm 36.89}{32}

t=\frac{55 + 36.89}{32} \ or \ t=\frac{55- 36.89}{32}

t=\frac{91.89}{32} \ or \ t=\frac{18.11}{32}

t=2.9 \ or \ t=0.6

The value of t is t = 0.6 because this denotes the time taken by the ball to reach a height of 30 feet from the ground.

Therefore, the time taken by the ball to reach a height of 30 feet above the ground is 0.6 seconds.

5 0
3 years ago
Mary wants to buy candies with an amount of money she has in her pocket.  we know that if she had $3.20 more money she could bu
liubo4ka [24]

Answer:

the price per candy is $0.16

and she has $16.00 in her pocket.

Step-by-step explanation:

x = the money in her pocket.

y = the price per candy

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x - 2.4 = 85×y

y = (x - 2.4)/85

=>

x + 3.2 = 120×(x - 2.4)/85 = (24x - 57.6)/17

=>

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5 0
3 years ago
How would I figure this out?
andrew-mc [135]

Answer:

y = 23

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y =23

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substitute y = 23

6x + 35 = 23 + 88

Solve for x

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3 years ago
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