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3 years ago

5

Find the length and width of a rectangle when the width is 4ft. Shorter than the length. The perimeter of the rectangle is great

er than 72ft.

1 answer:

Delicious77 [7]3 years ago

6 0

Answer:

e

Step-by-step explanation:

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Construct a stem-and-leaf plot of the test scores 67 comma 72 comma 85 comma 75 comma 89 comma 89 comma 87 comma 90 comma 99 co

VMariaS [17]

Answer:

Option C. Stem Leaves 6 7 7 2 5 8 5 7 9 9 9 0 9 10 0

Option D.

Step-by-step explanation:

The data values are 67, 72, 85, 75, 89, 89, 87, 90, 99 and 100.

Arranging the data values in ascending order

67, 72, 75, 85, 87, 89, 89, 90, 99, 100

The stem and lead plot can be shown under and stem is denoted as "S" whereas leaves are denoted as "L".

S L

6 7

7 2 5

8 5 7 9 9

9 0 9

10 0

The longer row of stem indicates the higher frequencies and so the length of rows are similar to the heights of bars in histogram.

5 0

3 years ago

The slope of the line whose equation is given

rosijanka [135]

The slope is 9/1 hope i helped

8 0

3 years ago

Mr.smith has 238 eggs in the warehouse. He collected all another 122 eggs from his chickens yesterday. As he arranged all the eg

Aleksandr [31]

Answer:

238 + 122 – 28 = 332

There were 332 unbroken eggs left.

332 – 126 = 206

There were 206 white eggs left

5 0

2 years ago

Help me please thank you

podryga [215]

The answer is 79 im sure of it

8 0

3 years ago

Given f(x)=-1/7√16-x^2 find f^-1(x)

Vera_Pavlovna [14]

Answer:

$f^{-1}(x)=\pm \sqrt{49x^2-16}$

Not a function.

Step-by-step explanation:

The given function is;

$f(x)=-\frac{1}{7}\sqrt{16-x^2}$

Let $y=-\frac{1}{7}\sqrt{16-x^2}$

Interchange x and y;

$x=-\frac{1}{7}\sqrt{16-y^2}$

Solve for y;

$-7x=\sqrt{16-y^2}$

Square both sides

$(-7x)^2=(\sqrt{16-y^2})^2$

$49x^2^2=16-y^2$

$49x^2^2-16=y^2$

$y=\pm \sqrt{49x^2-16}$

The inverse is

$f^{-1}(x)=\pm \sqrt{49x^2-16}$

$f^{-1}(x)=\pm \sqrt{49x^2-16}$ is not a function because one x-value maps onto to different y-values.

6 0

3 years ago