The area would be approximately 153.94.
The area of a circle is pie multiplied by r^2.
So you have the radius, which is r. Plug in r. Technically you have two numbers because pie equals approximately 3.14.
A=3.14(7)^2
Answer:
x² + (y + 5)² = 100
Step-by-step explanation:
If the center of the circle is 5 units below the origin, its x coordinate is 0 and its y-coordinate is -5. So, the center of the circle is at (0, -5).
Using the equation of a circle with center (h, k)
(x - h)² + (y - k)² = r² where r = radius of the circle.
Given that r = 10 units, and substituting the values of the other variables into the equation, we have
(x - h)² + (y - k)² = r²
(x - 0)² + (y - (-5))² = 10²
x² + (y + 5)² = 100
which is the equation of the circle.
Find the median of each set of data. 12, 8, 6, 4, 10, 1 7 6, 3, 5, 11, 2, 9, 5, 0 5 30, 16, 49, 25
professor190 [17]
Answer:
first 7 then 5 and 27.5
Step-by-step explanation:
Answer:
100
Step-by-step explanation:
because 4, 3, and 2 all make 180 and 4 and 2 are both 40 so you add that which makes 80 and then you take 180 and subtract 80 which gives you 100
Answer:
Option A is right
Step-by-step explanation:
In any data set, we find that the range is the difference between maximum and minimum. The range cannot give full information about the variability of the data set.
Outliers are the ones which are either below Q1-1.5IQR or Q3+1.5IQR
Thus Inter quartile range, the difference between I quartile and III quartile gives a better idea about variability and also outlier.
Hence out of the four options given, we find that option B is the right one.
Option
A. The IQR is the best measure of variability because the distribution has an outlier.