Answer:
true
Step-by-step explanation:
Alright, here it is
w=(q+p)/(q-pq)
factor out the q in the bottom part
w=(q+p)/[(q)(1-p)]
multiply both sides by q
wq=(q+p)/(1-p)
add 1 to both sides, but add (1-p)/(1-p) to the right side since that equals 1
wq+1=(q+1+p-p)/(1-p)=(q+1)/(1-p)
multiply both sdies by (1-p)
(wq+1)(1-p)=q+1
divide both sdies by (wq+1)
1-p=(q+1)/(wq+1)
subtract 1 from both sdies
-p=[(q+1)/(wq+1)]-1
multiply by -1
p=-[(q+1)/(wq+1)]+1 or
Answer:
a=1, b=2, c=5, d=1, e=6
Step-by-step explanation:

So 
The probability that a person could not give up cell phone but could give up television can be expressed as the probability of No could give up cell phone and Yes could give up television, P(NnY) = 0.39
<u>From the two way probability table given</u> :
- Let, probability that a person could not give up cell phone = N
- Probability that a person could give up television = Y
The intersection of Y and N = P(Y n N)
- The probability value at the intersection point using the table given ls 0.39
Therefore, the probability of YnN is 0.39
Learn more :brainly.com/question/18153040
Answer: yes it is equivalent!
Step-by-step explanation:
all you do is take away the parentheses and then it is the same exact thing!