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Alik [6]
2 years ago
8

Draw a diagram and solve the problem below to see how far Cecil went on the tightrope.

Mathematics
1 answer:
lakkis [162]2 years ago
6 0
It’s 19 thththtththt

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Find the trinomial below 4x^2 + 12x + 9
gulaghasi [49]

Answer:

4x²  +  12x  +  18

Step-by-step explanation:

This would be the trinomial.

4 0
3 years ago
Read 2 more answers
Which best describes the meaning of the statement if A then B
Oliga [24]

Answer:

a => b   \equiv   ( \neg a   \ \lor   \ b )

Step-by-step explanation:

You can understand the statement from many perspectives, but in terms of proposition logic it is best to understand it as   "negation of a" or "  b" in mathematical terms is written like this

a => b   \equiv   ( \neg a   \ \lor   \ b )

You can show that they are logically equivalent because they have the same truth table.

 

3 0
3 years ago
| 2x + 2y = 10<br> y = 5+x
melisa1 [442]
2x + 2(5+x)=10
2x+10+2x=10
4x+10=10
4x=0
X=0
6 0
3 years ago
Teresa graphs the following 33 equations: y=2xy=2x, y=x2+2y=x2+2, and y=2x2y=2x2. She says that the graph of y=2xy=2x will event
Neko [114]
The correct question is 
<span>Teresa graphs the following 3 equations: y=2x, y=x2+2, and y=2x2. She says that the graph of y=2x will eventually surpass both of the other graphs. Is Teresa correct? Why or why not?

we have that
y=2x
y=x</span>²+2
y=2x²

using a graph tool
see the attached figure

<span>We can affirm the following
</span>the three graphs present the same domain-----> the interval (-∞,∞)

The range of the graph y=2x  is the interval (-∞,∞)

The range of the graphs y=x²+2 and y=2x² is the interval [0,∞)

therefore
<span>Teresa is not correct because the graph of y = 2x will not surpass the other two graphs since in the interval of [0, infinite) the three graphs present the same range</span>

3 0
3 years ago
On a coordinate plane, a dashed straight line has a negative slope and goes through (0, 2) and (4, 0). Everything below and to t
yanalaym [24]

Answer:

Option C.

Step-by-step explanation:

A dashed straight line has a negative slope and goes through (0, 2) and (4, 0).

The given inequality is

y

We need find the point which is a solution to the given linear inequality.

Check the given inequality for point (2, 3).

3

3    

This statement is false. Option 1 is incorrect.

Check the given inequality for point (2, 1).

1

1

This statement is false. Option 2 is incorrect.

Check the given inequality for point (3, -2).

-2

-2

This statement is false. Option 3 is correct.

Check the given inequality for point (-1,3).

3

3

This statement is false. Option 4 is incorrect.

Therefore, the correct option is C.

4 0
2 years ago
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