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slavikrds [6]
3 years ago
7

If sin(x) = cos(y) for acute angles x and y, how are the angles related?

Mathematics
1 answer:
Vesnalui [34]3 years ago
6 0

Answer:

b. complementary

Step-by-step explanation:

-Complementary angles are angles that add up to 90°.

-These are usually the two acute angles in the right triangle.

#To verify, lets take the two angles 30° and 60°:

Cos \ 60\textdegree=0.5\\\\Sin \ 30\textdegree=0.5\\\\\therefore Sin \ 30\textdegree=Cos \ 60 \textdegree=0.5

#We can reverse as:

Sin \ 60\textdegree=0.86603\\\\Cos \ 30\textdegree=0.86603\\\\\therefore Sin \ 60\textdegree=Cos \ 30\textdegree=0.86603

Hence, two angles are said to be complimentary if they sum up to 90°.

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Shiva bought a second hand motorcycle for rupees 153200 his spent to 1200 to repair it and sold it to vishnu at 8% loss. how muc
Alecsey [184]

Answer:

142048

Step-by-step explanation:

8 0
3 years ago
Please help me with this:
Katen [24]

Answer:

She used 22 paper fans, 66 balloons, and 32 streamers.

Step-by-step explanation:

In order to solve this problem, we need to find out the value of the paper fans. Because we need to find out the balloon amount, which is 3 times as much. The amount of streamers is 12 fewer than two times. We can't find it out just yet since we don't know the value of the paper fans. To find it out:

First, let's call the amount of paper fan as "x".

Then, we need to find out the amount of balloons. It is 3 times x. Which is the same as 3x.

The equation is now x + 3x + (?) = 120

We need to find out the amount of the (?).

So, to do that, it says the value is 12 fewer than 2 times the value of x. (x, because it is the amount of paper fans.)

It should be 2x-12.

Now, the equation is x+3x+2x-12=120.

Once we solve it, we know "x" is 22.

Now, we can multiply 3 by 22. Which is 66.

Then we can multiply 22 by 2, which is 44, and subtract 12, which is 32.

To double check, 22 + 44 + 32 = 120.

That's your answer!

5 0
3 years ago
Read 2 more answers
Plzz help steps if possible if not its ok j=i just need to pass this class
hammer [34]

Answer:

\text{(B) }\cos 40^{\circ}=\frac{x}{60}

Step-by-step explanation:

In any triangle, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse (longest side) of the triangle. (a/h)

The angle marked 40 degrees has an adjacent side of x and the hypotenuse of the triangle is 60.

Therefore, we have the equation:

\boxed{\cos 40^{\circ}=\frac{x}{60}}

6 0
3 years ago
Which is a graph of y=-1/2x- 2?
cricket20 [7]

Answer:

the first one

y-intercept (0,-2)

x-intercept (-4,0)

8 0
3 years ago
Prove that the diagonals of a parallelogram bisect each other​
Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof :\begin{array}{ |c| c |  c |  } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In  \: \triangle ^{s}  \:AOB \: and \: COD  } \\  \sf{(i)}&  \sf{ \angle \: OAB =  \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\  \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\  \sf{(iii)} &\sf{ \angle \: OBA=  \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\  \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}.          Proved ✔

♕ And we're done! Hurrayyy! ;)

# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P

☄ Hope I helped! ♡

☃ Let me know if you have any questions! ♪

\underbrace{ \overbrace  {\mathfrak{Carry \: On \: Learning}}} ☂

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

5 0
3 years ago
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