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3 years ago

If sin(x) = cos(y) for acute angles x and y, how are the angles related?

Mathematics

1 answer:

Vesnalui [34]3 years ago

6 0

Answer:

b. complementary

Step-by-step explanation:

-Complementary angles are angles that add up to 90°.

-These are usually the two acute angles in the right triangle.

#To verify, lets take the two angles 30° and 60°:

$Cos \ 60\textdegree=0.5\\\\Sin \ 30\textdegree=0.5\\\\\therefore Sin \ 30\textdegree=Cos \ 60 \textdegree=0.5$

#We can reverse as:

$Sin \ 60\textdegree=0.86603\\\\Cos \ 30\textdegree=0.86603\\\\\therefore Sin \ 60\textdegree=Cos \ 30\textdegree=0.86603$

Hence, two angles are said to be complimentary if they sum up to 90°.

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Point T has coordinates (10,20). To calculate the coordinates of point T′ in the image,

Hatshy [7]

Answer: $T'(18,36)$

Step-by-step explanation:

For this exercise it is important to know the definition of "Dilation".

A Dilation is defined as a transformation in which the Image (The figure obtained after the transformation) and the Pre-Image (The original figure before the transformation) have the same shape but have different sizes.

If the Dilation is centered at the origin, and knowing the scale factor of $\frac{9}{5}$ , you need to multiply each coordinate of the point T by the scale factor in order to find the coordinates of the Image T'.

Knowing that the point T has the following coordinates:

$T(10,20)$

You get that the coordinates of the Image T' are the shown below:

$T'=(\frac{9}{5}*10,\frac{9}{5}*20)\\\\T'=(18,36)$

6 0

3 years ago

Help!! Math question

aksik [14]

18 - 7x = -20.52.5 = 7xx = 5/14 (c)

5 0

3 years ago

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What is the area of the obtuse triangle Below?

bija089 [108]

Answer:

45 sq.units

Step-by-step explanation:

to get area of a triangle, it would be base*height/2, so 15*6/2 would be 90/2, which ends up being 45, which is the answer.

4 0

2 years ago

Find the difference of the following polynomials:<br> (-2r4 + 3r3 - 10) and (4r4 - p3 + 2r2 + 7).

Vilka [71]

$-6 r^{4}+4 r^{3}-2 r^{2}-17$ is the difference between $-2 r^{4}+3 r^{3}-20 \text { and } 4 r^{4}-p^{3}+2 r^{2}+7$

Step-by-step explanation:

Given equations,

$-2 r^{4}+3 r^{3}-20 \text { and } 4 r^{4}-p^{3}+2 r^{2}+7$

Difference of the polynomial is written as

$=-2 r^{4}+3 r^{3}-20-\left(4 r^{4}-p^{3}+2 r^{2}+7\right)$

Open the brackets and multiply with -1 the whole expression $\left(4 r^{4}-p^{3}+2 r^{2}+7\right)$ becomes

$=-2 r^{4}+3 r^{3}-20-4 r^{4}+p^{3}-2 r^{2}-7$

$=-6 r^{4}+4 r^{3}-2 r^{2}-17$

This is the difference of given two polynomials is $-6 r^{4}+4 r^{3}-2 r^{2}-17$ .

4 0

3 years ago

Given that 32✓2=2^a , find the value of a

NNADVOKAT [17]

Answer:

Step-by-step explanation:

All you need is something that when you divide the right side (the way I've written it) by 2, you get 32 sqrt(2). So a must also have sqrt(2) in it. In addition, it must also have 16 as well so that when you multiply by 2, you get 32.

2a = 32*sqrt(2) Divide by 2

a = 16*sqrt(2)

5 0

3 years ago

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