Use the difference of squares factorization - that for any numbers a and b, (a-b)(a+b)=a^2-b^2.

We have:

(x^2+1)(x^2-1)=x^4-1

In addition:

(x-1)(x+1)=x^2-1, so we have:

(x^2+1)(x+1)(x-1)

As our complete factorization.

5 0

3 years ago

Read 2 more answers

Sandra runs at a rate of 8 miles in

Harman [31]

She runs 8/45 miles per min

3 0

3 years ago

the cable installer charges 42.50 per hour plus a 60.00 service charge. Your father's firm hires him to took up his company inte

Mama L [17]

The equation would be c=42.5x+60
C is cost
X is number of hours

3 0

3 years ago

Please help me with it is for homework<br><br> I really need help please help me

Solnce55 [7]

Answer:

See explanation

Step-by-step explanation:

Given two expressions:

$2(s+0.5)+2(s+1.5)$

and

$4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4$

a. When $s=0,$

then

$2(s+0.5)+2(s+1.5)=2(0+0.5)+2(0+1.5)=1+3=4$

and

$4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4=4\left(\dfrac{1}{2}\cdot 0+\dfrac{1}{4}\cdot 0\right)+4=4$

b. When $s=12,$

then

$2(s+0.5)+2(s+1.5)=2(12+0.5)+2(12+1.5)=2\cdot 12.5+2\cdot 13.5=25+27=52$

and

$4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4=4\left(\dfrac{1}{2}\cdot 12+\dfrac{1}{4}\cdot 12\right)+4=4(6+3)+4=4\cdot 9+4=36+6=40$

c. Since the value of both expressions at s = 12 are different, the expressions are not equivalent.

6 0

3 years ago