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3 years ago

14

What is two percent of £150?

1 answer:

svetlana [45]3 years ago

6 0

1% of 150 = 1.5 x 2 = 3

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Subtract -2k3 + k2 - 9 from 5k3 - 3k + 7.

tankabanditka [31]

5k3-3k+7-(-2k3+k2-9)
basically rewrite with simple algebra principles
15k-3k+7-(-6k+2k-9)
split up the parenthesis
15k-3k+7+6k-2k+9
sort them
15k-3k+6k-3k+7+9
short down by adding up the similar factors
answer: 18k+18
factorise
18(k+1)
both forms are right

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3 years ago

Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $30,

REY [17]

Answer:

a) 217

b) 1351

c) 5403

Step-by-step explanation:

Given that:

confidence interval (c) = 0.95

$\alpha =1-0.95=0.05\\\frac{\alpha }{2} =\frac{0.05}{2}=0.025$

The Z score of $\frac{\alpha }{2}$ is from the z table is given as:

$Z_{\frac{\alpha }{2} }=Z_{0.025}=1.96$

Range = $45000 - $30000 = $15000

The standard deviation (σ) is given as:

$\sigma=\frac{Range}{4} =\frac{15000}{4}=3750$

Sample size (n) is given as:

$n=(\frac{Z_{\frac{\alpha}{2} }\sigma}{E} )^2$

a) E = $500

$n=(\frac{Z_{\frac{\alpha}{2} }\sigma}{E} )^2= (\frac{1.96*3750}{500} )^2$ ≈ 217

b) $n=(\frac{Z_{\frac{\alpha}{2} }\sigma}{E} )^2= (\frac{1.96*3750}{200} )^2$ ≈ 1351

c) $n=(\frac{Z_{\frac{\alpha}{2} }\sigma}{E} )^2= (\frac{1.96*3750}{100} )^2$ ≈ 5403

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3 years ago

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