Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer:
Step-by-step explanation:
5 + 6 = 11 x 2 - 1 = 21 therefore its 21
Answer:
thanks
Step-by-step explanation:
Answer:
Leg of an isosceles right triangle is 7.99 long.
Step-by-step explanation:
Given:
Length of the hypotenuse =11.31
To find:
Length of the leg of an isosceles right triangle =?
Solution:
According to Pythagorean's Theorem, we have
-----------------------------(1)
Here were are given as isosceles triangle, so the two sides will be of same length
So equation 1 can be rewritten as


Substituting the value of hypotenuse





a = 7.99
Answer:
10 books per box
Step-by-step explanation:
40÷4
=10
10×4= 40