<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
I hope this helps you
1=?.7
?=1/7
(4 2/3) / (4 1/5) = 1.111
Split the object then find the 2 areas then subtract
Answer:
step 1. A, B,D are incorrectly written as these are not all coordinates. they must be written (x, y)
step 2. so the question becomes is C a quadratic
step 3. The x values must be evenly spaced. the x values are evenly spaced by a difference of 4
step 4. write out the y values: -126, -14, 2, 18
step 5. write out the differences: 140, 16, 16
step 6. write out the differences: -124, 0.
step 7. after doing this twice the numbers nust be the same for this to be a quadratic which they aren't
step 8. C is not a quadratic.
