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3 years ago

351 students in 27 classes _____ students in each class

Mathematics

2 answers:

77julia77 [94]3 years ago

7 0

Answer:

Step-by-step explanation:

351 divided by 27 = 13

aleksklad [387]3 years ago

3 0

If there are 351 students and 27 classes, there are 13 students in each class.

351 divided by 27 = 13

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Find the value of n in this equation.

lisabon 2012 [21]

Answer:

D. 9

=========================

<h2>Given </h2>

Triangle with:

Base of n² -3,
Midsegment of 39.

The value of n.

<h2>Solution</h2>

As per definition of midsegment, it is connecting the midpoints of two sides and its length is half the length of the opposite side of the triangle.

So we have:

(n² - 3)/2 = 39

Solve it for n:

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n² = 81
n = √81
n = 9

Correct choice is D.

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$\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1$

Rewrite and expand the given limand as the product

$\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)$

Then using the known limit above, it follows that

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