Explanation:
its answer is displacement reaction
use a mortar & pestle to grind the solute into smaller particles, thus increasing the surface area.
Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Planet, Star, Solar system,Galaxy
The difference of molarity and molality is in the units:
Molarity is expressed in mol solute / L solution;
<span> while Molality is
expressed in mol solute / kg solvent</span>
Since no other data is given, let us assume that the
contribution of methanol on the total volume is negligible. So that,
Molality = (20.3 mol / L) (1 L / 0.858 kg)
Molality = 23.66 m
<span>The closest answer is letter C. 23.7 m</span>
