Answer:
The correct answer is option B.
Explanation:
Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.
The equation for the ionization of the magnesium hydroxide is given as:
xS yS
Here, S = concentration of compound dissolved in solvent via dissociation
Expression for the solubility product of
will be:
![K_{sp}=[A^{y+}]^x[B^{x-}]^y\\\\K_{sp}=(xS)^x\times (yS)^y](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BA%5E%7By%2B%7D%5D%5Ex%5BB%5E%7Bx-%7D%5D%5Ey%5C%5C%5C%5CK_%7Bsp%7D%3D%28xS%29%5Ex%5Ctimes%20%28yS%29%5Ey)
As we can see,
![K_{sp}\propto [S]](https://tex.z-dn.net/?f=K_%7Bsp%7D%5Cpropto%20%5BS%5D)
- Higher the value of [S] more will be solubility of compound in a solvent.Hence, more soluble it will be.
- Lower the value of [S] less will be solubility of compound in a solvent.Hence, less soluble it will be.
Hence, the correct answer is option B.
This has only only three sig figs because it is 546.000 the zeros are just place holders so thus meaning they are not significant. It is just another way to write 546 because in that number there is also 3 sig figs. They are just trying to throw you off. Just watch out because if the example is 540 then it is just two significant digits, and it were to be 540. then it be three cause that "." makes the zero significant. <span />
Answer:
no sé m i e r d a ..............
Explanation:
<h2>
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Answer: 1. 5
2H202 -> 2H2O + O2 ; 2 + 2 +1 = 5
Answer:
λ = 2.38 × 10^(-7) m
Explanation:
We are given the work function for palladium as 503.7 kJ/mol.
Now let's convert this to KJ/electron.
We know from avogadro's number that;
1 mole of electron = 6.022 × 10^(23) electrons
Thus,
503.7 kJ/mol = 503.7 × 1/(6.022 × 10^(23)) = 8.364 × 10^(-22) KJ/electron = 8.364 × 10^(-19) J/electron
Formula for energy of a photon is;
E = hv
Where;
h is Planck's constant = 6.626 × 10^(-34) J.s
v is velocity
Now, v = c/λ
Where;
c is speed of light = 3 × 10^(8) m/s
λ is wavelength of light.
Thus;
E = hc/λ
Making λ the subject, we have;
λ = hc/E
λ = (6.626 × 10^(-34) × 3 × 10^(8))/(8.364 × 10^(-19))
λ = 2.38 × 10^(-7) m