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NeTakaya
3 years ago
10

What do scientists use to increase the surface area of a solute

Chemistry
2 answers:
marta [7]3 years ago
6 0

use a mortar & pestle to grind the solute into smaller particles, thus increasing the surface area.


Rudik [331]3 years ago
4 0

They use mortar and pestle to grind the solute into smaller particles.

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If someone told you they had a career in either ecology, paleontology, or botany, what area of science is this?
cestrela7 [59]

Natural Science. Although I don't know whether paleontology counts as a nautral science.

6 0
3 years ago
Will mark brainliest. What is the main function of the circulatory system in multicellular organisms?
just olya [345]

Answer:

D: to transport materials through the body.

Explanation:

A: to bring oxygen into the lung. is incorrect because it's respiratory system

B: to put carbon dioxide into all the blood vessels carbon dioxide is exhaled out of the body

C: to expel waste products from the body. is excretory system

4 0
3 years ago
Write the formulas of the compounds formed by specified cations with the following anions: OH-, ClO3-, SO3^2-, HPO4^2-. . . . Ex
Katena32 [7]
In the follow

<span>1)N<span>H4</span>OH,N<span>H4</span>Cl<span>O3</span>,(N<span>H4</span><span>)2</span>S<span>O3</span>,(N<span>H4</span><span>)2</span>HP<span>O4</span></span> <span>2)Al(OH<span>)3</span>,Al(Cl<span>O3</span><span>)3</span>,A<span>l2</span>(S<span>O3</span><span>)3</span>,A<span>l2</span>(HP<span>O4</span><span>)3</span></span> <span><span>3)Pb(OH<span>)4</span>,Pb(Cl<span>O3</span><span>)4</span>,Pb(S<span>O3</span><span>)2</span>,Pb(HP<span>O4</span><span>)2</span></span></span>
7 0
3 years ago
Read 2 more answers
What is the pH of this solution?
Vesnalui [34]

Answer:

pH = 11.216.

Explanation:

Hello there!

In this case, according to the ionization of ammonia in aqueous solution:

NH_3+H_2O\rightleftharpoons NH_4^++OH^-

We can set up its equilibrium expression in terms of x as the reaction extent equal to the concentration of each product at equilibrium:

Kb=\frac{[NH_4^+][OH^-]}{[NH_3]} \\\\1.80x10^{-5}=\frac{x*x}{0.150-x}

However, since Kb<<<1 we can neglect the x on bottom and easily compute it via:

1.80x10^{-5}=\frac{x*x}{0.150}\\\\x=\sqrt{1.80x10^{-5}*0.150}=1.643x10^{-3}M

Which is also:

[OH^-]=1.643x10^{-3}M

Thereafter we can compute the pOH first:

pOH=-log(1.643x10^{-3}M)\\\\pOH=2.784

Finally, the pH turns out:

pH=14-2.784\\\\pH=11.216

Regards!

5 0
3 years ago
What is the pH of 0.0001 M NaOH
kow [346]
Well. NaOH is a base. That's the first thing you need to watch for.
So to find the pOH, you take -log(.0001)
that would be 4. So now you have the pOH and <u>you still need to find the pH
</u>To find pH from pOH, you take 14(the maximum pH,sorta)-pOH(in this case 4)
14-4=10 The pH of NaOH is 10
5 0
3 years ago
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