Please help!!

Mathematics

1 answer:

Leokris [45]2 years ago

5 0

Answer:

Examples of sinusoidal graphs can be found in wave patterns, temperature patterns over extended period of times.

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How do you solve for r. -2r-5=18

r-ruslan [8.4K]

The answer is r=-23/2

3 0

3 years ago

Read 2 more answers

Indicate in standard form the equation of the line passing through the given point and having the given slope. r(4, 0), m = 5

Brrunno [24]

Y = mx + b....m is the slope and b is the y intercept
slope(m) = 5...(4,0)...x = 4 and y = 0
now we sub our info into y = mx + b...we r looking for b, the y intercept
0 = 5(4) + b
0 = 20 + b
-20 = b
so ur equation is y = 20x - 20...but we need it in standard form
Ax + By = C

y = 20x - 20....subtract 20x from both sides
-20x + y = -20...multiply by -1 to make x positive
20x - y = 20 <== standard form

5 0

3 years ago

Solve this for Brainliest! See the attachment [Level - GCSE]

madreJ [45]

Answer:

$x = 3 + 4\sqrt{3}$

Step-by-step explanation:

OPQ is a right angle triangle.

Using Pythagoras

$x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0$

Using quadratic formula

$x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}$