For Data Set B, we see that the data is more varied. The absolute deviations are 4, 3, 2, 5. The average of these absolute deviations is 3.5. MAD_B = (4+3+2+5)/4 =3.5 M ADB
Hence, The average of these absolute deviations is 3.5.
Answer: 0.14
Step-by-step explanation:
1) Find the total #of seniors. To do this add up 25+5+5 = 35.
2)Since we know the number of seniors that work just do 5/35. This simplifies to 0.14 rounded to the nearest hundreth.
Answer:
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Step-by-step explanation:
A line segment forms when it has two end points
