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RideAnS [48]
3 years ago
15

What is a 5 if an = an - 1 2 and the first term is 8?

Mathematics
1 answer:
iren [92.7K]3 years ago
7 0

Answer:

-3

Step-by-step explanation:

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Three thousand three hundred and seventy eight
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Greatest common factor <br>3a^3+9a^2​
BaLLatris [955]

Answer:

27A+81A =108

Step-by-step explanation:

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If you help me I give you branliest
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option 4

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4 0
3 years ago
Find LCM of 9-p^2 and p^2+3p​
snow_lady [41]

Answer:

(3+p)

Step-by-step explanation:

solution

first expression=9-P^2

=3^2 - P^2

=(3+P) (3-p)

second expression=p^2 + 3p

= p(3+p)

Therefore lCM= (3+p)

3 0
3 years ago
Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Andre45 [30]

For this case, we must indicate which of the given functions is not defined forx = 0

By definition, we know that:

f (x) = \sqrt {x} has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative when x = 0.

While y = \sqrt {x + 2} if it is defined for x = 0.

f(x)=\sqrt[3]{x}, your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

y = \sqrt [3] {x-2} with x = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x + 2}with x = 0: y = \sqrt [3] {2}in the same way is defined.

Answer:

y = \sqrt {x-2}

Option b


6 0
4 years ago
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