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swat32
3 years ago
12

B) Find the measurements of a rectangk with a perimeter of26cm and an area of 1600cm​

Mathematics
1 answer:
Llana [10]3 years ago
4 0

Answer:

b) Find the measurements of a rectangk with a perimeter of

26cm and an area of 1600cm​

There is no way to get an area of 1600 cm using a perimeter as small as 26 cm.

Step-by-step explanation:

perimeter = 2(L + W) = 26, then L + W = 13, so L = 13 - W

area = L x W = 1600

substitute for L:

(13 - W)W = 1600

13W - W² = 1600

-W² + 13W = 1600

-W² + 13W - 1600 = 0

W² - 13W + 1600 = 0

Not possible

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Answer:

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Step-by-step explanation:

The question is poorly formatted. The original question is:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

We have:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

Open bracket

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^{3* \frac{2}{3}}) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

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Factorize

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