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nika2105 [10]
2 years ago
13

Find f(3) if f(x)=x^3 + 2x^2-x-1

Mathematics
1 answer:
Wittaler [7]2 years ago
4 0

Answer:

\underline{ \boxed{f(3) = 41}}

Step-by-step explanation:

if \to \: f(x)=x^3 + 2x^2-x-1 \\ then \: f(3) =  {3}^{3}  + 2( {3)}^{2}  - 3 - 1 \\ f(3) = 27 + 18 - 4 \\ f(3) = 41

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The product of two consecutive odd integers is 63. If x is the smallest of the integers, write an equation in terms of x that de
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Answer:

Step-by-step explanation: This is the quadratic function:

h(x)=ax²+bx+c

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we assume that h(0)=0

Therefore:

a(0)²+b(0)+c=0

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With the equations (1) and (2) we make a system of equations:

a+b=58

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we can solve this system of equations by reduction method.

-(a+b=58)

2a+b=56

---------------------

a=-2

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2a+b=56

-------------------

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