All categories

2 years ago

Find f(3) if f(x)=x^3 + 2x^2-x-1

Mathematics

1 answer:

Wittaler [7]2 years ago

4 0

Answer:

$\underline{ \boxed{f(3) = 41}}$

Step-by-step explanation:

$if \to \: f(x)=x^3 + 2x^2-x-1 \\ then \: f(3) = {3}^{3} + 2( {3)}^{2} - 3 - 1 \\ f(3) = 27 + 18 - 4 \\ f(3) = 41$

You might be interested in

What is the opposite of the opposite of the opposite of 29?

Bond [772]

Answer:

-29

Step-by-step explanation:

First opposite: -29

Second opposite: 29

Third opposite: -29

3 0

2 years ago

If (x-y)^2=100 and xy=20. what's the value of x^2+y^2?

ahrayia [7]

$(x-y)^2=x^2-2xy+y^2=(x^2+y^2)-2(xy)\\\\\text{We have}\ (x-y)^2=100\ \text{and}\ xy=20.\\\\\text{Substitute}\\\\100=(x^2+y^2)-2(20)\\100=(x^2+y^2)-40\qquad\text{add 40 to both sides}\\\\140=(x^2+y^2)\\\\Answer:\ \boxed{x^2+y^2=140}$

8 0

3 years ago

Read 2 more answers

Please help asap!!!!! due at 2:00 pm

sladkih [1.3K]

Answer:

16.6%

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Please help!! I'll make you Brainlest!! Thanks!!

nirvana33 [79]

16. The open circle is excluded and closed is included.
x≤-6
x>2

17. The open circle is excluded so the inequality would be: -3<x<2

4 0

3 years ago

HELP IN NEED!

laiz [17]

Answer:

$AB=12\sqrt{3}\ cm$

Step-by-step explanation:

If AB is tangent to the circle, then angle ABO is right angle and triangle AOB is special $30^{\circ}-60^{\circ}-90^{\circ}$ triangle. In this triangle, the leg that is opposite to the angle of 30° is half of the hypotenuse. Thus,

$AO=2BO=2\cdot 12=24\ cm.$

By the Pythagorean theorem,

$AB^2=AO^2-BO^2,\\ \\AB^2=24^2-12^2,\\ \\AB^2=576-144=432,\\ \\AB=12\sqrt{3}\ cm.$

6 0

3 years ago