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3 years ago

P=−4b 2 +6b−9 Q=7b 2 −2b−5 P−Q= Your answer should be a polynomial in standard form.

Mathematics

1 answer:

shepuryov [24]3 years ago

3 0

Answer:

−11b^2+8b−4

Step-by-step explanation:

−4b2+6b−9−7b2+2b+5

Simplify by adding terms.

11b2+8b−4

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How is the sum expressed in sigma notation? 11 + 17 + 23 + 29 + 35 + 41

Ann [662]

<h3>The sum expressed in sigma notation is:</h3>

$11+17+23+29+35+41=\sum\limits_{i=1}^{6}5+6i$

Solution:

Given that,

11 + 17 + 23 + 29 + 35 + 41

We have to express the sum in sigma notation

Analyse the series

5 + 6(1) = 11

5 + 6(2) = 17

5 + 6(3) = 5 + 18 = 23

5 + 6(4) = 5 + 24 = 29

5 + 6(5) = 5 + 30 = 35

5 + 6(6) = 5 + 36 = 41

Thus the series goes on like this:

5 + 6(n) , where n = 1 to 6

This can be expressed in sigma notation as:

$11+17+23+29+35+41=\sum\limits_{n=1}^{6}5+6n$

We can expand the sigma notation and verify the results

$\sum\limits_{i=1}^{6}5+6i=(5+6(1))+(5+6(2))+(5+6(3))+(5+6(4))+(5+6(5))+(5+6(6))\\\\\\\sum\limits_{i=1}^{6}5+6i=(5+6)+(5+12)+(5+18)+(5+24)+(5+30)+(5+36)\\\\\\\sum\limits_{i=1}^{6}5+6i=11+17+23+29+35+41$

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P=−4b 2 +6b−9 Q=7b 2 −2b−5 ​P−Q= Your answer should be a polynomial in standard form.

P=−4b 2 +6b−9 Q=7b 2 −2b−5 P−Q= Your answer should be a polynomial in standard form.