Question

Pls answer Both questions

Answer 1

Answer:

$-\dfrac{1}{2}ab^{12}$

$\dfrac{w^{10}}{3y^{4}}}$

Step-by-step explanation:

$\dfrac{-2a^2b^4}{4ab^{-8}} =$

$= \dfrac{-2}{4}a^{2-1}b^{4-(-8)}$

$= -\dfrac{1}{2}ab^{12}$

$\dfrac{-5w^4y^{-2}}{-15w^{-6}y^{2}} =$

$= \dfrac{-5}{-15}w^{4 - (-6)} y^{-2 - 2}$

$= \dfrac{1}{3}w^{10} y^{-4}$

$= \dfrac{w^{10}}{3y^{4}}$