Rearrange

to give

Let

be a variable 'p' and so we can write

as

Rewrite the equation in terms of 'p'

where

using the quadratic formula

and subsitute the value of



There are two value of p; 125 and -27
Now we find the value of x
Earlier we substitute

for

and

for

When

,
![x= \sqrt[3]{125}=5](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%5B3%5D%7B125%7D%3D5%20)
When
![p = -27, x= \sqrt[3]{-27}=-3](https://tex.z-dn.net/?f=p%20%3D%20-27%2C%20x%3D%20%5Csqrt%5B3%5D%7B-27%7D%3D-3%20)
So the final answer is the two values of x;
x = 5 OR x = -3
Answer:
B
Step-by-step explanation:
r -5
Answer:
bottom 2 shapes
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
It goes -1.33333, -2, -1, -.08, -.07 and that's incorrect.