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3 years ago

Indicate whether or not 1/√2 belongs to each set of numbers

Mathematics

1 answer:

Oksi-84 [34.3K]3 years ago

6 0

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Hey mate Whole numbers is your Answer

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Evaluate -5g - 6 for g = -2

Feliz [49]

Plug in g equals -5 x -2 which equals 10 because 2 negatives are a positive then 10-6 equals 4

The anwser is 4

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3 years ago

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What are the solutions to the quadratic equation (5y + 6)2 = 24?

Ivenika [448]

Answer:

y = $\frac{2\sqrt{6} }{5} -\frac{6}{5}$ OR y = $\frac{-2\sqrt{6} }{5} -\frac{6}{5}$

Step-by-step explanation:

Our quadratic equation is: (5y + 6)² = 24.

The first step is to square root both sides:

5y + 6 = ±√24 = ±2√6

Now subtract 6 from both sides:

5y = ±2√6 - 6

Finally divide by 5 from both sides:

y = $\frac{2\sqrt{6} }{5} -\frac{6}{5}$ OR y = $\frac{-2\sqrt{6} }{5} -\frac{6}{5}$

And, those are the solutions to the equation.

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3 years ago

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Ede4ka [16]

Answer:

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Step-by-step explanation:

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3 years ago

The permitir of the garden is (6x+2) units. Find the length of the missing side .

Snezhnost [94]

Answer: ? = x + 1

Step-by-step explanation:

The perimeter of the garden is x + 3x + 1 + x + ?

The perimeter of the garden is also (6x + 2)

Therfore:

x + 3x + 1 + x + ? = 6x + 2

Collect like terms:

5x + 1 + ? = 6x + 2

Subtract 5x from both sides:

1 + ? = x + 2

Subtract 1 from both sides:

? = x + 1

You cannot find ? as a number, only in terms of x.

5 0

3 years ago

Find the missing dimension of the prism. Round your answer to the nearest hundredth.

Nitella [24]

Answer:

$x = 6.99in$

Step-by-step explanation:

Given

$l =2in$

$Volume = 72.66in^3$

See attachment for prism

Required

Find x

The prism has a regular hexagon base

The base area is calculated as:

$Base\ Area= \frac{3\sqrt 3}{2}l^2$

This gives:

$Base\ Area= \frac{3\sqrt 3}{2} * 2^2$

$Base\ Area= \frac{3\sqrt 3}{2} * 4$

$Base\ Area= 3\sqrt 3 * 2$

$Base\ Area= 6\sqrt 3$

Side x represents the height.

So, we have:

$Volume = Base\ Area*x$

Make x the subject

$x = \frac{Volume }{ Base\ Area}$

$x = \frac{72.66in^3}{6\sqrt 3 in^2}$

$x = \frac{72.66}{6\sqrt 3}in$

$x = \frac{12.11}{\sqrt 3}in$

$x = 6.99in$ --- approximated

6 0

3 years ago

Indicate whether or not 1/√2 belongs to each set of numbers​

Indicate whether or not 1/√2 belongs to each set of numbers