If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
Answer:

Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
<h3>Part (a)</h3>
f(x - 1) is the translation of f(x) one unit right.
So the graph is exactly same shape but shifted right one unit.
<h3>Part (b)</h3>
f(x) has vertex (-1, 2)
<u>The function y = f(-x) + 2 will have the vertex changed as per rule:</u>
<u>So the new vertex is:</u>
- (-1, 2) → (-(-1), 2 + 2) = (1, 4)
Answer:
B yes
Step-by-step explanation: