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mr Goodwill [35]
2 years ago
10

The radius of a circle is 13 miles. What is the circle's area?

Mathematics
2 answers:
Makovka662 [10]2 years ago
5 0

Solution:

<u>We know that:</u>

  • Radius: 13 miles
  • Area of circle = (π)(r²)

<u>Finding the area of the circle:</u>

  • Area of circle = (π)(r²)
  • => Area of circle = (3.14)(13²)
  • => Area of circle = 3.14 x 169
  • => Area of circle = 530.66 m²
lesantik [10]2 years ago
3 0

A=π×r×2=

=π×13×2 =

530.92916 mi²

here is your answer

hope it will help u

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Write this number in word form 890,704
zhannawk [14.2K]

Answer: eight hundred ninety thousand, seven hundred four

8 0
3 years ago
If pencils sell at 6 for 59 cents how many pencils can be bought for 2.95
Olegator [25]
We already know from the given data that 6 pencils can be bought for 59 cents. We have to determine the number of pencils that can be bought for $2.95.
So
Price of 6 pencils = 59 cents.
Price of 1 pencil = (59/6) cents
                           = 9.83 cents
Now total amount in hand for buying pencils = $2.95
                                                                       = 295 cents
Then the number of pencils that can be bought for 295 cents = (295/9.83)
                                                                                                   = 30.01
So the maximum number of pencils that can be bought for $2.95 is 30 pencils.
4 0
3 years ago
Read 2 more answers
Quotient of 120 and 10
saw5 [17]
Quotient is the result of division
120 divided by 10 = 12

therefore your quotient would be 12
5 0
3 years ago
Read 2 more answers
What is the rate of change from x = n to x = 2n?​
puteri [66]

Answer:

\dfrac{-8}{\pi}

Step-by-step explanation:

The rate of change of the function f(x) from point x_1 to point x_2 can be calculated using formula

\dfrac{f(x_2)-f(x_1)}{x_2-x_1}

Given

x_1=\pi\\ \\x_2=2\pi

From the graph of the function

f(x_1)=f(\pi)=4\\ \\f(x_2)=f(2\pi)=-4

So, the rate of change is

\dfrac{f(x_2)-f(x_1)}{x_2-x_1}=\dfrac{-4-4}{2\pi -\pi}=\dfrac{-8}{\pi}

5 0
3 years ago
Does anyone understand how to do this
Lerok [7]

Answer:

Step-by-step explanation:

I understand it!  (But I'm a high school math teacher so it might be unfair!) ; )

Anyway you have 2 numbers.  You don't know what they are so we will call them x and y.  Our first statement says that these numbers multiply to equal 120.  So that first equation is

xy = 120

Our second statement says that they add to -22.  So that second equation is

x + y = -22

Now we need to find the 2 numbers.  We have 2 unknowns, x and y.  That means that we have to have 2 equations.  No more than 2 no less than 2.  Solve the first equation for y.  It doesn't matter which equation you pick and which variable you choose to solve for.  If you do the work correctly, you will get the correct answers either way.  Solving the first equation for y gives you:

y=\frac{120}{x}

Now tht we have a value for y, we can use the substitution property of equality to sub that value into the second equation for y:

x+\frac{120}{x}=-22

Instead of finding a common denominator, we are going to eliminate x in the denominator altogether.  Do this by multiplying everything by x to get

x^2+120=-22x

Get everything on one side of the equals sign and factor:

x^2+22x+120=0

Because 12 * 10 = 120 and 12 + 10 = 22, our factors are 12 and 10:

x^2+12x+10x+120=0

Use factoring by grouping now.  

(x^2+12x)+(10x+120)=0

From the first set of parenthesis you can factor out an x, and from the second set you can factor out a 10:

x(x + 12) + 10(x + 12) = 0

Now factor out the common x + 12 to get a factored quadratic:

(x + 12)(x + 10) = 0

By the Zero Product Property, either x + 12 = 0 or x + 10 = 0.  Solving both for x gives you x = -12 or x = -10.

If x = -12, then

-12 + y = -22 so

y = -10

If x = -10, then

-10 + y = -22 so

y = -12.

The combinations of x and y are:

If x = -12, y = 10

If x = -10, y = -12

It doesn't matter which one is which.  They are not asking you to specifically define x and y.  They are asking you to find the numbers, and you did!

6 0
3 years ago
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