The expression that is a prime polynomial is:
B. 
.
<h3>What is a prime polynomial?</h3>
A prime polynomial is a polynomial that cannot be factored.
In this problem, item b gives a prime polynomial, as:
- In item a, 3 is a common factor, hence the polynomial can be factored.
- In item c, x is a common factor, hence the polynomial can be factored.
- In item d, the polynomial can be factored according to it's roots.
More can be learned about prime polynomials at brainly.com/question/26388060
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Answer:
415/619
Step-by-step explanation:
619 is a prime number, so the fraction is in simplest form already.
Answer:
option (a) f(x)= 1/x+2
Step-by-step explanation:
(a) f(x) = 1/ x+2
To find the restriction for domain , we set the denominator =0 and solve for x
x+2 =0, so x=-2
When x=-2 then denominator becomes 0 that is undefined.
So, domain is all real numbers except -2
(b) f(x)= 2x
In this function, there is no denominator or square root or log function
so there is no restriction for x, hence domain is all real numbers
(c) f(x) = 2x-2
In this function, there is no denominator or square root or log function
so there is no restriction for x, hence domain is all real numbers
f(x) = 1/ sqrt(x+2)
if we have square root in the denominator then we set the denominator >0 and solve for x. because square root of negative values are undefined
x+2>0, x>-2
Hence domain is all real numbers that are greater than -2
The y intercept of the graphed function and the equation are both -2
(I'm not entirely sure what the question is asking as some of it is blocked out from the drop down box?)
Answer:
Step-by-step explanation:
What did you include in your response? Check all that apply.
There would be an open circle at (2, 1). <u>Yes</u>
There would be a closed circle at (2, 3). <u>Yes</u>
There would be an open circle at (4, 3). <u>Yes</u>
There would be a closed circle at (4, −4). <u>Yes</u>
Endpoints that are not included in the domain of a particular piece of a function are represented by an open circle. <u>Yes</u>
