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zvonat [6]
3 years ago
9

1. z²-9z=66 2. y²+16y=17 3. 2h²-5h=-1

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Hello,

Starting with problem one:

Subtract 66 from both sides.

z2−9z−66=66−66

z2−9z−66=0

Use quadratic formula with a=1, b=-9, c=-66.

z = 9/2+1/2√345

Problem two:

Subtract 17 from both sides.

y^2+16y−17=17−17

y^2+16y−17=0

Factor left side of equation.

(y−1)(y+17)=0

Set factors equal to 0.

y−1=0 or y+17=0

y=1 or y=−17

ANSWER: y=1 or y=−17

Problem 3:

2h^2−5h−(−1)=−1−(−1)

2h^2−5h+1=0

Use quadratic formula with a=2, b=-5, c=1.

ANSWER: h=5/4+1/4√17

Have an amazing day.

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3 years ago
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While she was on holiday,Olga measured the temperature at the same time every day. Here are the results. Work out the median: Th
alukav5142 [94]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the required data are not given.

I will use the following data as an illustration of how to calculate median and range.

We have:

x: 11, 13, 14, 15, 18, 20

<u>Calculate range</u>

Identify the highest and the least

Highest = 20

Least = 11

So, the range is:

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Range =20-11

Range =9

<u>Calculate the median</u>

The number of data we are using is 6 (i.e. even).

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Median =\frac{1}{2}*7

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In this case, the median is the mean of the item at 3rd and 4th positions.

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3 0
3 years ago
Step by step solve for x the following problem... 34 - 5x + 2 (x - 2) = 15 ​
xz_007 [3.2K]

34-5x+2(x-2)=15

34-5x+2(x)(2) (-2)=15

34-5x+2x-4=15

30-3x=15

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7 0
4 years ago
52 + 6 × (5 − 3) − 10⁄2
GenaCL600 [577]
52+6×2− 2
10
​


2 Simplify
6
×
2
6×2 to
12
12.
52
+
12
−
10
2
52+12−
2
10
​


3 Simplify
10
2
2
10
​
to
5
5.
52
+
12
−
5
52+12−5

4 Simplify
52
+
12
52+12 to
64
64.
64
−
5
64−5

5 Simplify.
59
59
5 0
3 years ago
Read 2 more answers
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