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zvonat [6]
3 years ago
9

1. z²-9z=66 2. y²+16y=17 3. 2h²-5h=-1

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Hello,

Starting with problem one:

Subtract 66 from both sides.

z2−9z−66=66−66

z2−9z−66=0

Use quadratic formula with a=1, b=-9, c=-66.

z = 9/2+1/2√345

Problem two:

Subtract 17 from both sides.

y^2+16y−17=17−17

y^2+16y−17=0

Factor left side of equation.

(y−1)(y+17)=0

Set factors equal to 0.

y−1=0 or y+17=0

y=1 or y=−17

ANSWER: y=1 or y=−17

Problem 3:

2h^2−5h−(−1)=−1−(−1)

2h^2−5h+1=0

Use quadratic formula with a=2, b=-5, c=1.

ANSWER: h=5/4+1/4√17

Have an amazing day.

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I don't really speak Spanish but I'll guess that says

 How do I solve  y = 1 - 2.5

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\text{Given that }\$7000 \text{ is compounded semiannualy at a rate of }11\% \text{ for 21 years}\\
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\text{we know that the amount after t year when compounded is given by}\\
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A=P\left ( 1+\frac{r}{n} \right )^{nt}\\
\\
\text{here P is the principal amoount, so }P=7000,\\
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\text{r is the interest rate, }r=11\%=0.11\\
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\text{n is the number of times in a year, here semiannulay, so }n=2,\\
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\text{and t is the time, so }t=21\\
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\text{so the amount after 21 years is}

A=7000\left ( 1+\frac{0.11}{2} \right )^{2(21)}\\
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