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3 years ago

8

a rocket car on the bonneville salt flats is traveling at a rate of 640 miles per hour. how much is time would it take for the c

ar to travel 384 miles at this rate?

1 answer:

nikitadnepr [17]3 years ago

8 0

Roughly 36 minutes at that rate

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If a number is odd, then it has a remainder of 1 when divided by 2.

Dominik [7]

Answer:

A number is odd

Step-by-step explanation:

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3 years ago

WILL GIVE LOTS OF POINTS HELP SOLVE SOON, NUMBER 7

Nadusha1986 [10]

Answer: 4x + 3 = 39

Step-by-step explanation:

Because you don't know how much each pizza costs, you can write it as x.

You multiply x by 4 to get 4x and add 3 because thats how much the chips cost.

That added up should equal 39 because thats how much he spent.

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2 years ago

Read 2 more answers

(20 PTS) Please help!!!! I've been stuck for 1 hour already! :(

Sindrei [870]

We have: 10 + 7 = 17

Answer: 17

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2 years ago

Review the table showing wind speed, y, in miles per hour, measured x hours after midnight.

hodyreva [135]

The trigonometric function that best models the data is determined as y = 1.87sin(–0.29x + 4.79) + 6.13.

<h3>Trigonometric function that models the data</h3>

The trigonometric function that best models the data is determined as follows;

y = 1.87sin(-0.29x + 4.79) + 6.13

Use the above equation to check if its gives you values in the table;

<h3>when x = 1</h3>

y = 1.87sin(-0.29 x 1 + 4.79) + 6.13

y = 1.87sin(4.5 rad) + 6.13

y = 4.3

<h3>when x = 2</h3>

y = 1.87sin(-0.29 x 2 + 4.79) + 6.13

y = 1.87sin(4.21 rad) + 6.13

y = 4.49

<h3>when x = 4</h3>

y = 1.87sin(-0.29 x 4 + 4.79) + 6.13

y = 1.87sin(3.63 rad) + 6.13

y = 5.2

<h3>when x = 7</h3>

y = 1.87sin(-0.29 x 7 + 4.79) + 6.13

y = 1.87sin(2.76 rad) + 6.13

y = 6.8

<h3>when x = 9</h3>

y = 1.87sin(-0.29 x 9 + 4.79) + 6.13

y = 1.87sin(2.18 rad) + 6.13

y =7.7

<h3>when x = 10</h3>

y = 1.87sin(-0.29 x 10 + 4.79) + 6.13

y = 1.87sin(1.89 rad) + 6.13

y = 7.9

<h3>when x = 13</h3>

y = 1.87sin(-0.29 x 13 + 4.79) + 6.13

y = 1.87sin(1.02 rad) + 6.13

y = 7.72

<h3>when x = 17</h3>

y = 1.87sin(-0.29 x 17 + 4.79) + 6.13

y = 1.87sin(-0.14 rad) + 6.13

y = 5.9

<h3>when x = 20</h3>

y = 1.87sin(-0.29 x 20 + 4.79) + 6.13

y = 1.87sin(-1.01 rad) + 6.13

y = 4.6

Thus, the trigonometric function that best models the data is determined as y = 1.87sin(–0.29x + 4.79) + 6.13.

Learn more about trigonometry functions here: brainly.com/question/1143565

#SPJ1

8 0

2 years ago

A piece of wire 28 ft long is cut into two pieces. One piece is used to form a square, and the remaining piece is used to form a

marusya05 [52]

Answer:

Wire should be cut in two parts with the length = 15.69 ft and 12.31 ft

Step-by-step explanation:

Length of the wire = 28 ft has been cut in two pieces.

One piece is used to form a square and remaining piece to form a circle.

Let the length of the wire which forms the square is 'l' ft.

Area of the square = (side)²

Perimeter of the square = 4(side) = l

Length of one side = $\frac{l}{4}$

So, the area of the square = $\frac{l^{2}}{16}$ ft²

Now length of the remaining part = perimeter of the circle = (28 - l) ft

2πr = (28 - l)

r = $\frac{28-l}{2\pi }$

Area of the circle formed = πr²

= $\frac{\pi(28-l)^{2} }{4(\pi )^{2} }$

= $\frac{(28-l)^{2}}{4\pi }$

Combined area of the square and circle

= $\frac{l^{2}}{16}$ + $\frac{(28-l)^{2}}{4\pi }$

= $\frac{l^{2}}{16}$ + $\frac{(28-l)^{2}}{4\pi }$

Now to maximize the area we will find the derivative of the area with respect to l.

$\frac{dA}{dl}=\frac{d}{dl}[\frac{l^{2}}{16}+\frac{(28-l)^{2}}{4\pi}]$

= $\frac{d}{dl}[\frac{l^{2}}{16}+\frac{(28)^{2}+l^{2}-56l }{4\pi }]$

= $\frac{2l}{16}+\frac{(2l-56)}{4\pi }$

Now equate the derivative to zero.

$\frac{2l}{16}+\frac{(2l-56)}{4\pi }$ = 0

$(2l-56)=-\frac{2l}{16}\times 4\pi$

$(2l-56)=-\frac{\pi l}{2}$

$2l+\frac{\pi l}{2}=56$

$\frac{(4l+l\pi )}{2}=56$

l(4 + π) = 112

l(4 + 3.14) = 112

l = $\frac{112}{7.14}$

l = 15.69 ft

Length of the other part = 28 - 15.69 = 12.31 ft

Therefore, wire should be cut in two parts with the length = 15.69 ft and 12.31 ft

8 0

3 years ago