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gladu [14]
3 years ago
6

Simplify. 2x+7y+3x−4y please help

Mathematics
2 answers:
Mariulka [41]3 years ago
8 0

Answer:

<h2>5x +3y</h2>

Step-by-step explanation:

2x+7y+3x-4y\\\\\mathrm{Group\:like\:terms}\\=2x+3x+7y-4y\\\\\mathrm{Add\:similar\:elements:}\:2x+3x=5x\\=5x+7y-4y\\\\\mathrm{Add\:similar\:elements:}\:7y-4y=3y\\= 5x+3y

JulijaS [17]3 years ago
4 0

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

             \boxed{5x + 3y}

Let's simplify step-by-step.

2x+7y+3x-4y

= 2x+7y+3x-4y

Combine Like Terms:

2x+7y+3x-4y\\= ( 2x + 3x ) + ( 7y + -4y ) \\= 5x + 3y

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Have a great day/night!

❀*May*❀

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Answer:

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Step-by-step explanation:

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Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =
irga5000 [103]

Answer:  The required solution is y=50e^{0.1386t}.

Step-by-step explanation:

We are given to solve the following differential equation :

\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

\dfrac{dy}{y}=kdt.

Integrating both sides, we get

\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]

Also, the conditions are

y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50

and

y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.

Thus, the required solution is y=50e^{0.1386t}.

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Name a career in which one would have to use the phythagorean theorem.Give an example of when and how it would be used.Please wr
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Answer:

The careers that use Pythagoras theorem are mentioned below.

Step-by-step explanation:

The Pythagoras theorem states that the sum of squares of the two sides of right angled triangle is equal to the square of the length of the hypotenuse.

Let a, b and c be the sides of a right triangle where c is the length of the hypotenuse.Then

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Pythagoras theorem is used in daily life situations.

A surveyor looks through a telescope toward a measuring stick a fixed distance away, so that the telescope's line of sight and the measuring stick form a right angle.

It is also used to calculate the steepness of slopes and mountains.

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