Answer:
x=9
Step-by-step explanation:
Answer:
y=3*2+2
Step-by-step explanation:
y=3*2+2
=3*2=6
=6+2=7
y=7
Given:
The expression is
![\dfrac{\sqrt[3]{9}}{\sqrt[3]{4}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B9%7D%7D%7B%5Csqrt%5B3%5D%7B4%7D%7D)
To find:
The simplified form of given expression.
Solution:
We have,
![\dfrac{\sqrt[3]{9}}{\sqrt[3]{4}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B9%7D%7D%7B%5Csqrt%5B3%5D%7B4%7D%7D)
It can be written as
![\left[\because \dfrac{\sqrt[a]{x}}{\sqrt[a]{y}}=\sqrt[a]{\dfrac{x}{y}}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cdfrac%7B%5Csqrt%5Ba%5D%7Bx%7D%7D%7B%5Csqrt%5Ba%5D%7By%7D%7D%3D%5Csqrt%5Ba%5D%7B%5Cdfrac%7Bx%7D%7By%7D%7D%5Cright%5D)
Therefore, the simplified form of given expression is
.
Note: We can further simplify this expression but be need use exponential properties.
<span>First we calculate z using the formula:
z = (x - μ)/σ</span>
Where:
x = our variable, 10
μ = mean, 8
σ = standard dev, 2
Substituting known
values:<span>
z = (10 - 8)/2
z = 2/2
z = 1
Using the tables of
the normal distribution to find the p-value with z = 1
p = 0.8413
Since we want
"greater than 10”, we need to subtract the probability from 1
therefore
p* = 1 - 0.8413 = <span>0.1587</span></span>