Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer:
A counterexample for a conjecture is the statement that disproves a conjecture.
Step-by-step explanation:
To find : What is a counterexample for the conjecture?
Solution :
A conjecture is an educated guess but not yet proven. It is possible that next example shown the conjecture wrong.
A counterexample is an example that disproves or disagree a conjecture.
For example : Prime numbers - 3,7,11,23
Conjecture - All prime numbers are odd
Counterexample - 2
→ 2 is a prime number but not odd, it is an even number.
Answer:
The Parenthesis tells you what operation to do first.
Step-by-step explanation:
Why? Because you have to get rid of the Parenthesis before getting rid of anything else in the problem.
The circle equation is in the format (x – h)2 + (y – k)2= r2, with the center being at the point (h, k) and the radius being "r".
x²+y²-8x-6y+2 =0 -----(a)
(x-4)² = x² - 8x + 16
(y-3)² = y² - 6y + 9
Equation (a) can be rewritten as:
(x-4)² + (y-3)² + 2 - 16 - 9 = 0
(x-4)² + (y-3)² = 23
The coordinates for the center of the circle is: ( 4,3)
The radius is √23=4.8
