You can use the distance equation.. d = rt
d = distance = 645
r = rate = 215 mph
t = time = ???? find the time
645 = 215t
645/215 = 215t / 215
3 = t
t = 3
It took 3 hours
I like to reduce everything by half if I don't already know the answer.

It just so happens that is the reduced fraction.
All I did was halve 18, which is 9, and halve 34, which is 17.
Answer:
Andy basically has two stickers
First you divide L+W by 2 and you would get A/2=L+W then you would subtract L and get A/2 -L=W
Answer:
1,041.9feet
Step-by-step explanation:
Given the height of the rocket expressed as
y = -16x² + 245x + 104
At maximum height, dy/dx = 0
dy/dx = -32x+245
0 = -32x+245
32x = 245
x = 245/32
x = 7.65625
Get the maximum height
Recall that;
y = -16x² + 245x + 104
Substitute the value of x;
y = -16(7.65625)² + 245(7.65625) + 104
y = -937.890625 + 1,875.78125 + 104
y = 1,041.890625feet
Hcne the maximum height to the nearest foot is 1,041.9feet