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mafiozo [28]
3 years ago
11

If m PLEASE EXPLAIN NOT SURE

Mathematics
2 answers:
Luba_88 [7]3 years ago
7 0

IF M WHAT???...???????

Alexus [3.1K]3 years ago
3 0
If m??? How does this make any sense
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Yes I wanted to know what is the answer ​
jek_recluse [69]

Answer:

14 flats

5 plants

Step-by-step explanation:

First you would do 89/6 but since that doesn’t divide nicely you can do 90/6 to get 15 then subtract 1 since the original number was 89 and you would get 14

The 14 times 6 would get you 84

Then subtract 84 from 89 and you get 5 plants left over ^^

7 0
2 years ago
The area of a square is 81 centimeters find the length of the length find the diagonal
EleoNora [17]

Length = √area  = √81 = 9

diagonal = √2 * side = √2*9 = 9√2

5 0
3 years ago
Find the sum of 10 + 5i and its complex conjugate.<br> Write your answer in the form a + bi
gogolik [260]

Answer:

20.

Given, complex number is 10+5i .

We need to find sum of the given complex number and its conjugate. The conjugate of 10+5i is 10-5i. Therefore, the sum will be 10+5i+10−5i=20.

7 0
3 years ago
Please help me answer one of these!
babunello [35]

This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


There aren't any parallel lines involved in the above described construction, so I'll skip the first one.


2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.


4. ... construct the perpendicular bisector ... a different way?


Maybe what I first described is different; there are no parallel lines.



8 0
3 years ago
Solve for x: 2/3+1/3x=2x
velikii [3]

Answer:

x=2/5 or

x=0.4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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