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3 years ago

Find the volume of the sphere. Enter an exact answer using 3.14 for pi

Mathematics

1 answer:

svetoff [14.1K]3 years ago

7 0

Answer:

The volume for the sphere is 904.78

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What is the surface area of this rectangular pyramid

musickatia [10]

Answer:

54 That Is how big it is

ur welcom

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3 years ago

Give y=3x-5/x+6 Calculate y' and check the sign

jenyasd209 [6]

Answer:

x = -6

-18+4y=0 => 4y=18 =>y=18/4=9/2

Y=5

3x+20=0 => x=3x= -20=> x= -20/3

Step-by-step explanation:

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3 years ago

Cindy takes a sheet of paper and cuts from one corner to the opposite corner, making two triangles. If the piece of paper is 5 i

Westkost [7]

Answer:

Perimeter of one of the triangle= $17.071 inch$

Step-by-step explanation:

The triangle has:

$Perpendicular= 5 inch\\Base = 5 inch \\Diagonal(Hypotenuse)=?$

Using the Pythagorean Theorem;

$( Hypotenuse)^2=(Perpendicular)^2+(Base)^2\\H^2= 5^2+5^2\\H^2=25+25\\H^2=50\\$

$H=\sqrt{50}\\or\\H=7.071 inches$

The Perimeter of one of the triangle is =

$Perpendicular+Base+Hypotenuse\\5+5+7.071\\17.071inch$

This is equal for the other triangle.

6 0

3 years ago

Which relation is a function of x? A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 2, 2, 3. Column

Trava [24]

Answer:

Column 1 is labeled x with entries negative 3, negative 2, 4, 7. Column 2 is labeled y with entries negative 1, 5, 0, negative 1

Step-by-step explanation:

When a value is repeated for an x-entry, the relation is not a function. The last choice describes a table with unique x values.

8 0

3 years ago

Read 2 more answers

a test for diabetes results in a positive test in 95% of the cases where the disease is present and a negative test in 07% of th

Mila [183]

Answer:

0.9378 = 93.78% probability that a randomly selected person has diabetes, given that his test is positive.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive test

Event B: Person has diabetes.

Probability of a positive test:

0.95 out of 0.1(person has diabetes).

0.007 out of 1 - 0.1 = 0.9(person does not has diabetes). So

$P(A) = 0.95*0.1 + 0.007*0.9 = 0.1013$

Probability of a positive test and having diabetes:

0.95 out of 0.1. So

$P(A \cap B) = 0.95*0.1 = 0.095$

What is the probability that a randomly selected person has diabetes, given that his test is positive?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.095}{0.1013} = 0.9378$

0.9378 = 93.78% probability that a randomly selected person has diabetes, given that his test is positive.

7 0

3 years ago