the question in English
The route of a stage of a cycle tour is 213 km long and a cyclist covers 2/3 of the route in five hours.
a) How many kilometers are left to finish the stage?
b) If he continues with the same average speed, how much time does he have left to finish the stage?
Step 1
we know that
1) Total kilometers of a stage is 
2) The cyclist covers 
of the route
so
the kilometers remaining to finish the stage is equal to
therefore
<u>the answer Part a) is </u>
Step 2
<u>Find the average speed of the cyclist</u>
we know that
the speed is equal to
we have
substitute
Step 3
<u>Find the time remaining to finish the stage</u>
we know that
Solve for the time
we have
substitute
therefore
<u>the answer Part b) is</u>
Answer:
-3.5, -3, -1.5, -1, 2
Step-by-step explanation:
Answer:
-3
1 + 4 sqrt( 241 )
1 - 4 sqrt( 241 )
Step-by-step explanation:
We need minus lambda on the entries down the diagonal. I'm going to use m instead of the letter for lambda.
[-43-m 0 80]
[40 -3-m 80]
[24 0 45-m]
Now let's find the determinant
(-43-m)[(-3-m)(45-m)-0(80)]
-0[40(45-m)-80(24)]
+80[40(0)-(-3-m)(24)]
Let's simplify:
(-43-m)[(-3-m)(45-m)]
-0
+80[-(-3-m)(24)]
Continuing:
(-43-m)[(-3-m)(45-m)]
+80[-(-3-m)(24)]
I'm going to factor (-3-m) from both terms:
(-3-m)[(-43-m)(45-m)-80(24)]
Multiply the pair of binomials in the brackets and the other pair of numbers;
(-3-m)[-1935-2m+m^2-1920]
Simplify and reorder expression in brackets:
(-3-m)[m^2-2m-3855]
Set equal to 0 to find the eigenvalues
-3-m=0 gives us m=-3 as one eigenvalue
The other is a quadratic and looks scary because of the big numbers.
I guess I will use quadratic formula and a calculator.
(2 +/- sqrt( (-2)^2 - 4(1)(-3855) )/(2×1)
(2 +/- sqrt( 15424 )/(2)
(2 +/- sqrt( 64 )sqrt( 241 )/(2)
(2 +/- 8 sqrt( 241 )/(2)
1 +/- 4 sqrt( 241 )
Is there anything else included in the question? possible a picture or anything?
Answer:
Step-by-step explanation:
7. 6 + 1/2 + 1/2 = 7
8. shade it
9. 1.3 + 0.2 + 0.4 = 1.9 0.8 + 0.2 + 0.7 = 1.7
10. (2)(4)(5) = 40
(4)(5)(1) = 20
(5)(6)(0) = 0
hope dis helps ^-^
