Help me please explain do not need work just explain THANK YOU I NEED HELP
1 answer:
Alright,
you will need to solve for each variable to find if they got the equation correctly or not..
Let's start with h
isolate h
(1/2)h = A/(b1+b2)
Now we need to get rid of 1/2 we may do so by multiplying both sides by 2
h = 2(A/(b1+b2))
And that's not how they did it for h so Option D doesn't apply
Let's see C
Also doesn't apply since they multiplied 2 only by A rather than A/h
Let's see B
Also not correct they made the same mistake as with option C
Let's see A
again same mistake
when multiplying both sides by 2
the 2 should be as following
I believe you should contact your instructor and explain that non of the options is right.
you will need to solve for each variable to find if they got the equation correctly or not..
Let's start with h
isolate h
(1/2)h = A/(b1+b2)
Now we need to get rid of 1/2 we may do so by multiplying both sides by 2
h = 2(A/(b1+b2))
And that's not how they did it for h so Option D doesn't apply
Let's see C
Also doesn't apply since they multiplied 2 only by A rather than A/h
Let's see B
Also not correct they made the same mistake as with option C
Let's see A
again same mistake
when multiplying both sides by 2
the 2 should be as following
I believe you should contact your instructor and explain that non of the options is right.
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Answer:
The distance reduces to 0 as you go from 0° to 90°
Step-by-step explanation:
The question requires you to find the distance using different values of L and check the trend of the values.
Given C=2×pi×r×cos L where L is the latitude in ° and r is the radius in miles then;
Taking r=3960 and L=0° ,
C=2××3960×cos 0°
C=2××3960×1
C=7380
Taking L=45° and r=3960 then;
C= 2××3960×cos 45°
C=5600.28
Taking L=60° and r=3960 then;
C=2××3960×cos 60°
C=3960
Taking L=90° and r=3960 then;
C=2××3960×cos 90°
C=2××3960×0
C=0
Conclusion
The values of the distance from around the Earth along a given latitude decreases with increase in the value of L when r is constant