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jek_recluse [69]
3 years ago
11

Draw two different figures that each have a perimeter of 20 units

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Answer:

1

⬛️⬛️⬛️⬛️

⬛️⬛️⬛️⬛️

⬛️⬛️⬛️⬛️            (4 by 6)

⬛️⬛️⬛️⬛️

⬛️⬛️⬛️⬛️

⬛️⬛️⬛️⬛️

2

⬛️⬛️⬛️⬛️⬛️⬛️⬛️

⬛️⬛️⬛️⬛️⬛️⬛️⬛️          (7 by 3)

⬛️⬛️⬛️⬛️⬛️⬛️⬛️

Step-by-step explanation:

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(PLEASE HELP ) A falcon flies 800,000 meters in 4 hours. Use the formula d = rt, where d represents distance, r represents rate,
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Answer:

r = d/t

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r = 200, kilometers/hour

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Step-by-step explanation:

Given

) A falcon flies 800,000 meters in 4 hours.

thus distance = 800, 000 meters

1 km = 1000 meters

thus distance in km=  800, 000 meters/1000 = 800 km

t = h hours

Part A: Rearrange the distance formula, d = rt, to solve for rate.

d = rt

dividing both sides by t

d/t = rt/r = r

thus. r = d/t

Part B: Find the falcon's rate in meters per hour.

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r = 800, 000 meters/ 4 hours = 200, 000 meters/hour

thus, rate =  200, 000 meters/hour

Part C: Find the falcon's rate in kilometers per hour.

we know d in km = 800 km as shown above

thus

rate = 800 km/4 hours = 200 km/hour

Part D: Which unit, meters, or kilometres, makes more sense to use in this scenario, and why

we know that standard unit of speed is

km/hour and m/sec

we know that that every unit is divided into from to large so that if the value is large or small we can use the appropriate unit and thus it is simpler to look the data and analyze it.

since here distance is very large , hence it is better to use km /hour

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\leadsto f( \rm x) =  - (x - 3)(x - 5)

\\  \\

\leadsto f( \rm x) =   - ( {x}^{2}  - 5x - 3x + 15) \\

\\  \\

\leadsto f( \rm x) =   - ( {x}^{2}   - 8x + 15) \\

\\  \\

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