Let's get the data out of the problem:
Nv = 18
Ov = 12
Now, we can apply in this equation that relates the new and the old values:
i = Nv / Ov
i = 18 / 12
i = 1.5
Now, we just consider what has passed from 1, and this is 0.5, converting to percentage it is:
p = 0.5 . 100
p = 50%
The increase was 50%.
Hope it helps.
A) 1/6
B) 5/6
C) 1
D) 20
Explanation:
A) There is one 6 on a 6-sided die, out of 6 numbers.
B) There are 5 numbers that are not 6 on a 6 sided die, out of 6 numbers.
C) P( 6 or ~6) = P(6) + P(~6) = 1/6 + 5/6 = 6/6 = 1
D) 1/6(120) = 120/6 = 20
A jar contains 133 pennies....a bigger jar contains 1 2/7 times as much
so the bigger jar contains :
1 2/7 * 133
9/7 * 133 =
1197/7 =
171 pennies <===
Answer:
1875L = 1.875x10^6 mL
multiply by density to get 2.14x10^6
multiply by percentage to get 6.63x10^4 g of NaCl (66.3 kg)
Step-by-step explanation:
The 68-95-99.7 rule tells us 68% of the probability is between -1 standard deviation and +1 standard deviation from the mean. So we expect 75% corresponds to slightly more than 1 standard deviation.
Usually the unit normal tables don't report the area between -σ and σ but instead a cumulative probability, the area between -∞ and σ. 75% corresponds to 37.5% in each half so a cumulative probability of 50%+37.5%=87.5%. We look that up in the normal table and get σ=1.15.
So we expect 75% of normally distributed data to fall within μ-1.15σ and μ+1.15σ
That's 288.6 - 1.15(21.2) to 288.6 + 1.15(21.2)
Answer: 264.22 to 312.98
