We are told in the question that 1 carat is equal to 200 mg.
The Hope Diamond is 44.5 carats. Let's multiply the weight of 1 carat by 44.5 to get the weight of the Hope Diamond in mg:

The total weight of the Hope Diamond is 8,900 mg. However the question asks for the weight in grams. There are 1000 mg in 1 gram, so let's divide the known weight of the Hope Diamond in mg by 1000 to get the weight converted to grams:

Now we know that
the weight of the Hope Diamond is equal to 8.9 grams.
Answer:
4b
Step-by-step explanation:
The GCF is the largest number that will multiply into each term. It can be both numbers and letters.
12b = 2*2*3*b and 40b^4 = 2*2*2*5*b*b*b*b has GCF 2*2*b = 4b
Answer:
a = 39.2650873379cm
b = 11.5529459767cm
Step-by-step explanation:
a - Use the area of a triangle equation - 1/2 * a * b * Sin(C)
1/2 * 8 * 10 * Sin(79) = 39.2650873379cm
b - Use the cosine rule - c^2 = a^2 + b^2 - (2 * a * b * Sin(C)
64 + 100 - (2 * 8 * 10 * Cos(79)) = 133.4705607398
c = square root of 6.9396506484 = 11.5529459767cm
Put to however many significant figures / decimal places required.
:)
Answer: QE = 10
Step-by-step explanation: To solve this problem, it's important to understand that the diagonals of a parallelogram bisect each other.
This means that E is the midpoint of diagonal SQ.
So we can setup the equation x² + 9x = 4x + 6.
To solve this polynomial equation, set it equal to zero first.
So we have x² + 5x - 6 = 0 and we get (x + 6)(x - 1) = 0
when we factor the left side of the equation.
So this means that x = -6 or x = 1.
However, -6 will give us a negative length when we plug it in
to find QE so this will not work.
However, plugging 1 in will give us 10 as a length so QE = 10.
Answer:
A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:
A. closed at both ends
B. open at one end and closed at one end
C. open at both ends.
D. we cannot tell because we do not know the frequency of the sound.
The right choice is:
B. open at one end and closed at one end
.
Step-by-step explanation:
Given:
Length of the pipe,
= 120 cm
Its wavelength
= 480 cm
= 160 cm and
= 96 cm
We have to find whether the pipe is open,closed or open-closed or none.
Note:
- The fundamental wavelength of a pipe which is open at both ends is 2L.
- The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.
So,
The fundamental wavelength:
⇒ 
It seems that the pipe is open at one end and closed at one end.
Now lets check with the subsequent wavelengths.
For one side open and one side closed pipe:
An odd-integer number of quarter wavelength have to fit into the tube of length L.
⇒
⇒ 
⇒
⇒ 
⇒
⇒ 
⇒
⇒
So the pipe is open at one end and closed at one end
.