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REY [17]
3 years ago
15

Brgy. Mataas has a

Mathematics
1 answer:
MAVERICK [17]3 years ago
4 0

Answer:

Step-by-step explanation:

Your answer

40% of 365000 is = 146000

Mark it as Brainlist answer. Follow me.

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Solve for x <br><br> log(7x+1) = log(x-2) + 1
myrzilka [38]
Log(7x+1) - log(x-2) =1

log[(7x+1) / (x-2)] =1 or log[(7x+1) / (x-2)] =log10 (log10=1)

it means (7x+1) / (x-2) =10

Solving ===> x=7
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3 years ago
An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with μ = 44 and σ = 5.0. (a) What is
aalyn [17]

Answer:

Step-by-step explanation:

Using normal distribution,

z = (x - μ)/σ

μ= mean = 44 and

σ = standard deviation= 5.0

a) The probability that yield strength is at most 40=

P( x lesser than or equal to 40)

z = (40-44)/5= -0.8

Looking at the normal distribution table,

P( x lesser than or equal to 40) =0.2119

b) P(x greater than 62) = 1 - P(x lesser than or equal to 62)

z = (62-44)/5= 3.6

Looking at the normal distribution table,

P(x greater than 62) = 1 -0.99984

= 0.00016

c)P( 42 lesser than or equal to x lesser than or equal to 62)

= P(x lesser than or equal to 62) - P( x lesser than or equal to 40)

= 0.99987-0.2119= 0.78797

d) What yield strength value separates the strongest 75% from the others.

To get x for strongest 75, we get the z value corresponding to 0.75 from the table

z = 0.675= (x-44)/5

x = 3.375+44 = 47.375

The rest is 25% = 0.25

we get the z value corresponding to 0.25 from the table)

z = -0.67 = (x-44)/5

-3.35= x -44

x = -44+3.35= 40.65

yield strength value that separates the strongest 75% from the others

=47.375-40.65= 6.725

3 0
3 years ago
While shopping at Walmart, I had the option to buy either a 12 pack of Soda for $13, or I could buy a 24 pack for $24. Based on
ira [324]

Answer:

The 24 pack for 24 dollars!

Step-by-step explanation:

This is because you see that 12 is 1/2 of 24 and if you do 13x2 you get 26$ so for the 12 pack if you double it you will be paying 2$ more than if you got the OG 24 pack

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3 years ago
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