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3 years ago

Find the missing length using the Pythangorean Theorem and round the answer to the nearest tenth if necessary

Mathematics

1 answer:

UNO [17]3 years ago

5 0

B=6 i believe! if you use the pythagorean theorem (a^2+b^2=c^2) then you should be able to turn 8^2 and 10^2 into 64 and 100, respectively. 100-64=36 and the square root of 36 is 6. you can plug it in by calculating 8^2 + 6^2, which equals 100! hope this wasn't too confusing XD

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Prime factorization of 50

prisoha [69]

The prime factorization of 50 is 2x5x5

4 0

3 years ago

MATH-IXL , Look at the picture below to answer CORRECTLY. Only give me one right answer So i can mark yall as Brainliest!

Rom4ik [11]

The correct answer is 20 plz give me a like

8 0

3 years ago

You purchase a car worth $25077 and make a down payment of $3560. You intend to repay the balance of the car with month end car

zubka84 [21]

Answer:

value of buyout is $4185.74

Step-by-step explanation:

given data

car worth = $25077

down payment = $3560

monthly payment = $336 = 336 × 6 = $2016 per semi annually

time = 5 year = 10 half yearly

rate = 4.04 %

to find out

value of final buyout

solution

we know here loan amount will be 25077 - 3560 = $21517

and we find present value first by formula that is

present value = $\frac{amount(1+r)^t - 1}{r (1+r)^t}$

put here t = 10 and r = $\frac{4.04}{200}$

present value = $\frac{2016(1+\frac{4.04}{200})^10 - 1}{r (1+\frac{4.04}{200})^10}$

present value = 18089.96

loan unpaid amount is here

loan unpaid amount = 21517 - 18089.96

loan unpaid amount = $3427.04

now we calculate value of buyout

that is express as

amount = principal × $(1+r)^{t}$

amount = 3427.04 × $(1+\frac{4.04}{200})^{10}$

amount = 4185.74

so value of buyout is $4185.74

7 0

4 years ago

The probabilty that a student owns a car is 0.65 the porbability that a student owns a compuer is 0.82 the probability that a st

DanielleElmas [232]

Question: The probability that s student owns a car is 0.65, and the probability that a student owns a computer is 0.82.

a. If the probability that a student owns both is 0.55, what is the probability that a randomly selected student owns a car or computer?

b. What is the probability that a randomly selected student does not own a car or computer?

Answer:

(a) 0.92

(b) 0.08

Step-by-step explanation:

(a)

Applying

Pr(A or B) = Pr(A) + Pr(B) – Pr(A and B)................. Equation 1

Where A represent Car, B represent Computer.

From the question,

Pr(A) = 0.65, Pr(B) = 0.82, Pr(A and B) = 0.55

Substitute these values into equation 1

Pr(A or B) = 0.65+0.82-0.55

Pr(A or B) = 1.47-0.55

Pr(A or B) = 0.92.

Hence the probability that a student selected randomly owns a house or a car is 0.92

(b)

Applying

Pr(A or B) = 1 – Pr(not-A and not-B)

Pr(not-A and not-B) = 1-Pr(A or B) ..................... Equation 2

Given: Pr(A or B) = 0.92

Substitute these value into equation 2

Pr(not-A and not-B) = 1-0.92

Pr(not-A and not-B) = 0.08

Hence the probability that a student selected randomly does not own a car or a computer is 0.08

8 0

3 years ago

FOR BRAINLIST ANSWER AND 10 POINTS ANSWER ALL PLZ !!!!!

igor_vitrenko [27]

<h2>Greetings!</h2>

<h3>If you can see, every 4 minutes the amount of water is increasing at a constant rate. </h3>

197 - 153 = 44

285 - 241 = 44

<h3>This means that at 8 minutes, because there is 153 gallons already in, we can divide 8 by 4 to see how many groups of 4 minutes there were. </h3>

8 ÷ 4 = 2

So then we can subtract two lots of 44 from 153:

153 - (44 x 2) = 65

<h3>So the starting amount was 65.</h3>

<h3>The answer to B is the second option, because it is true that the amount of water is increasing. This is by 44 gallons per 4 minutes.</h3>

The amount of gallons per minute can be found out by dividing the amount by 4:

44 ÷ 4 = 11

<h3>So it is 11 gallons per minute.</h3>
<h2>Hope this helps!</h2>

3 0

3 years ago

Find the missing length using the Pythangorean Theorem and round the answer to the nearest tenth if necessary​

Find the missing length using the Pythangorean Theorem and round the answer to the nearest tenth if necessary