What is the pattern in the values as the exponents increase?

A box of cake mix calls for 3 cups of flour to be added to 14 ounces of butter. On a second box, the directions are to mix 4.5 c

Gnesinka [82]

Answer:

true

Step-by-step explanation:

because it is equal 3 cups of flour and u pulse the 4.5 after that butter we will get some better if we use the butter

may u understand i am cooker so i now

please mark as brainliest

7 0

3 years ago

Read 2 more answers

Find the number which when divided by 4 and increased by 12 is the same as when it is divided by 3 and decreased by 5

MatroZZZ [7]

Step-by-step explanation:

Let's make the number we're finding to be $a$ . So, it says that it will be divided by 4 and then added by 12 if we want this in algebraic expression it will be $\frac{a}{4} +12\\$ . It's also telling us that that expression is the same thing as our number divided by 3 and subtracted by 5. If we want an expression out of it it well be $\frac{a}{3} -5\\$ . Since they are the same, we have the equation below.

$\frac{a}{4} +12 = \frac{a}{3} -5\\$

All we have to do now is to find $a$ .

$\frac{a}{4} +12 = \frac{a}{3} -5 \\ \frac{a +48}{4} = \frac{a -15}{3} \\ (3)(a +48) = (a - 15)(4) \\ 3a +144 = 4a -60 \\ (60 -3a) + 3a +144 = 4a -60 +(60 -3a) \\ a = 204$

<h3>Answer:</h3>

Our number must be $204$ . I think

5 0

3 years ago

I NEED HELP!!!

andrey2020 [161]

Answer:

<h2>B. The amount of fuel used was lowest at speeds around 60km/h.</h2>

Step-by-step explanation:

The decreasing part is from (20,13) to (60,6), which gives an average rate of

$r=\frac{6-13}{60-20}=-\frac{7}{40}=-0.175$

Then, we have an increasing part from (60,6) to (120,10), which gives an average rate of

$r=\frac{10-6}{120-60}=\frac{4}{60}=0.067$

Basically, at 60 km/h the fuel used was 6 liters per 100 kilometers. Notice that the other velocities make the car to use more liters per kilometers.

Therefore, the amount of fuel used was lowest at speeds around 60 km/h.

6 0

2 years ago

What is the product?

Alona [7]

Answer:

$\boxed{- 12 {s}^{2} + 11st - 2 {t}^{2} }$

Step-by-step explanation:

$= > ( - 3s + 2t)(4s - t) \\ \\ = > - 3s(4s - t) + 2t(4s - t) \\ \\ = > ( ( - 3s) \times 4s )- (( - 3s) \times t) + (2t \times 4s) - (2t \times t) \\ \\ = > - 12 {s}^{2} - ( - 3st) + 8st - 2 {t}^{2} \\ \\ = > -12 {s}^{2} + 3st + 8st - 2 {t}^{2} \\ \\ = > - 12 {s}^{2} + 11st - 2 {t}^{2}$

7 0

3 years ago

Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in

Law Incorporation [45]

Answer:

(a) 900

(b) [567.35 , 1689.72]

(c) [23.82 , 41.11]

Step-by-step explanation:

We are given that a sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms i.e.;

Sample mean, $xbar$ = 290 Sample standard deviation, s = 30 and Sample size, n = 20

(a) Point estimate of the population variance is equal to sample variance, which is the square of Sample standard deviation ;

$\sigma^{2}$ = $s^{2}$ = $30^{2}$

$\sigma^{2}$ = 900

(b) 90% confidence interval estimate of the population variance is given by the pivotal quantity of $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2} __n_-_1$

P(10.12 < $\chi^{2}__1_9$ < 30.14) = 0.90 {At 10% significance level chi square has critical

values of 10.12 and 30.14 at 19 degree of freedom}

P(10.12 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 30.14) = 0.90

P( $\frac{10.12}{(n-1)s^{2} }$ < $\frac{1 }{\sigma^{2} }$ < $\frac{30.14}{(n-1)s^{2} }$ ) = 0.90

P( $\frac{(n-1)s^{2} }{30.14}$ < $\sigma^{2}$ < $\frac{(n-1)s^{2} }{10.12}$ ) = 0.90

90% confidence interval for $\sigma^{2}$ = $[\frac{19s^{2} }{30.14} , \frac{19s^{2} }{10.12}]$

= $[\frac{19*900 }{30.14} , \frac{19*900 }{10.12}]$

= [567.35 , 1689.72]

Therefore, 90% confidence interval estimate of the population variance is [567.35 , 1689.72] .

(c) 90% confidence interval estimate of the population standard deviation is given by ;

P( $\sqrt{\frac{(n-1)s^{2} }{30.14}}$ < $\sigma$ < $\sqrt{\frac{(n-1)s^{2} }{10.12}}$ ) = 0.90

90% confidence interval for $\sigma$ = $[\sqrt{\frac{19s^{2} }{30.14}} , \sqrt{\frac{19s^{2} }{10.12}} ]$

= [23.82 , 41.11]

Therefore, 90% confidence interval estimate of the population standard deviation is [23.82 , 41.11] .

7 0

3 years ago