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Yuri [45]
3 years ago
14

Scott wanted to start a lawn cutting service but needed to purchase a lawnmower. Sherif gave Scott $30 in exchange for company r

evenue. What does Sherif now have in Scott’s company?
A.
rebate

B.
investment

C.
stock

D.
bond
Business
2 answers:
NISA [10]3 years ago
5 0
B an investment the sherif invested
Mashcka [7]3 years ago
5 0

Answer:

The correct answer is C. Stock

Explanation:

I got it correct on Plato!

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Han and Leia Solo have been married for 24 years and have three children who qualify as their dependents (Jacen, 4; Jaina, 14; a
Ostrovityanka [42]

Other part of question attached

Answer and Explanation:

Answer and explanation attached

3 0
3 years ago
Are advanced receipts from customers treated as revenue at the time of receipt? Why or why not?
Ivanshal [37]

Answer:

No

Explanation:

The receipt received from customer is view as expense and expense is not a revenue.

The receipt can be issue after purchase or return of good. so in this particular case its not a revenue. Thank you

5 0
3 years ago
Brazil can produce 1 unit of sugarcane with 1 unit of labor and 1 iPod with 8 units of labor, and China can produce 1 unit of su
soldier1979 [14.2K]

Answer:

d. With trade, Brazil should specialize in sugar cane and China in iPods.

Explanation:

As from the given situation it can be seen that Brazil has an absolute advantage while producing the sugarcane as it takes one unit of labor for generating one unit of sugarcane

On the other hand, china has an absolute advantage for generating an ipod as it takes four unit of labor to generate one ipod

Therefore the option d is correct

4 0
3 years ago
Do you know the answer?
Ugo [173]

Answer:

d

Explanation:

4 0
3 years ago
A metal sphere of radius 15 cm has a net charge of 3.0 $ 10#8 C. (a) What is the electric field at the sphere’s surface? (b) If
denis-greek [22]

Answer:

E = 1.20 × 10^{4} N/C

V = 1800 V

x = 0.058 m

Explanation:

given data

radius = 15 cm

net charge = 3 × 10^{-8} C

electric potential decreased = 500 V

solution

we get here electric field at the sphere’s surface that is

electric field at the sphere’s surface E  =  \frac{q}{4\pi \epsilon _o R^2}   ............1

put here value

electric field at the sphere’s surface E  = \frac{3\times 10^{-8}\times 8.99\times 10^9}{ 0.15^2}    

E = 1.20 × 10^{4} N/C

and

potential on surface of sphere is

V =  \frac{q}{4\pi \epsilon _o R} ................2

V = \frac{3\times 10^{-8}\times 8.99\times 10^9}{ 0.15}  

V = 1800 V

and

now we get distance that is x

and we know here

ΔV = V(x) - V   ..............3

substitute here value

-500V = \frac{q}{4\pi \epsilon _o } \times (\frac{1}{R+x} - \frac{1}{R})

-500 V = {3\times 10^{-8}\times 8.99\times 10^9} \times (\frac{1}{0.15+x} - \frac{1}{0.15})

solve it we get x

x = 0.058 m

3 0
3 years ago
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