Answer:
Step-by-step explanation:
The diagram shows lines passing through the points of two equations.
We will determine the points through which the lines pass through on the graphs.
Looking at the line on the right hand side of the graph, the slope is
(y2-y1)/x(2-x1) where
y2= 0, y1 = 4
x2 = 3, x1=0
Slope, m = (0-4)/3-0
Slope = -4/3
Recall the equation of a straight line is y = mx + c
Where c is the intercept.
So the equation is y
y = -4x/3 + 4
Looking at the line on the left hand side of the graph, the slope is
(y2-y1)/x(2-x1) where
y2= 0, y1 = 2
x2 = -1, x1 =0
Slope, m = (0-2)/-1-0
Slope = -2/-1 = 2
Applying equation of a straight line is y = mx + c
The equation
y = 2x + 2
So the equations are
-4x/3 + 4. If x lesser than or equal 0
2x + 2. If x greater than 0
Answer:
it's answer "c" 1,8
Step-by-step explanation:
....
Answer:
Step-by-step explanation:
3
Answer: Third option.
Step-by-step explanation:
These are some transformations for a function f(x):
If 
, then the function is shifted down "k" units.
If 
, then the function is shifted right "k" units.
Knowing this we can describe the transformation from the graph of the function 
to the graph of the function 
. This is:
The function is the function but shifted right 3 units and shifted down 1 units.
Therefore, the correct option is the third one.
