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Murljashka [212]
3 years ago
11

I’m to lazy to do my own math so help anyone?

Mathematics
2 answers:
Sav [38]3 years ago
5 0

Answer: The answer is J

Step-by-step explanation:

Because 78 is the number in the middle since 75 and 76 are both smaller than 78 and 79 and 82 are both bigger than 78

trapecia [35]3 years ago
3 0

Answer:

J

Step-by-step explanation:

Because we want to find out how much it varies or in simple words the difference we can use Range to solve this because range is the difference from the largest number to the smallest number.

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Alchen [17]

See the attached picture:

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Solve for z z+9/2 = -3 A. –15 B. –10 C. 3 D. 8
Anuta_ua [19.1K]
You are given z+9/2 = -3. You are required to get the value of z. Since the equation is an example of an equality, you can easily get the value of z. The solution of the problem is,   Z + 9/2 = -3 Z = -3 – 9/2 <u>Z = -15/2 or -7.5</u> <span>There given choices does not contain the correct answer.</span>
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3 years ago
Read 2 more answers
What is GC? A.9 B.12 C.13 D.14
Kazeer [188]

Answer:

D

Step-by-step explanation:

For the median GC, the distance from the vertex to the centroid G is twice as long as the distance from the centroid to the midpoint, that is

GC = 2 GD = 2 × 7 = 14 → D

5 0
3 years ago
Which set of numbers is included in the solution set of 5-4x&lt;-7
Amanda [17]

Answer:

x > 3

Step-by-step explanation:

The inequality to solve is:

5 - 4x < - 7

We will solve this using same method as solving an equation. We will take numbers to one side and variables to another and multiply and divide accordingly.

So,

5-4x

That means "x is greater than 3", so we can write:

x > 3

4 0
3 years ago
The shares of the U.S. automobile market held in 1990 by General Motors, Japanese manufacturers, Ford, Chrysler, and other manuf
Mariana [72]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the purchase frequencies of new-car buyers follow the distribution of the shares of the U.S. automobile market for 1990.

You have one variable of interest:

X: Brand a new-car buyer prefers, categorized: GM, Japanese, Ford, Chrysler and Other

n= 1000

Observed frequencies

GM 193

Japanese 384

Ford 170

Chrysler 90

Other 163

a) The test to use to analyze if the observed purchase frequencies follow the market distribution you have to conduct a Goodness to Fit Chi-Square test.

The conditions for this test are:

- Independent observations

In this case, we will assume that each buyer surveyed is independent of the others.

- For 3+ categories: each expected frequency (Ei) must be at least 1 and at most 20% of the Ei are allowed to be less than 5.

In our case we have a total of 5 categories, 20% of 5 is 1, only one expected frequency is allowed to have a value less than 5.

I'll check this by calculating all expected frequencies using the formula: Ei= n*Pi (Pi= theoretical proportion that corresponds to the i-category)

E(GM)= n*P(GM)= 1000*0.36= 360

E(Jap)= n*P(Jap)= 1000*0.26= 260

E(Ford)= n*P(Ford)= 1000*0.21= 210

E(Chrys)= n*P(Chrys)= 1000*0.09= 90

E(Other)= n*P(Other)= 1000*0.08= 80

Note: If all calculations are done correctly then ∑Ei=n.

This is a quick way to check if the calculations are done correctly.

As you can see all conditions for the test are met.

b) The hypotheses for this test are:

H₀: P(GM)= 0.36; P(Jap)= 0.26; P(Ford)= 0.21; P(Chrys)= 0.09; P(Other)= 0.08

H₁: At least one of the expected frequencies is different from the observed ones.

α: 0.05

X^2= sum \frac{(Oi-Ei)^2}{Ei} ~~X^2_{k-1}

k= number of categories of the variable.

This test is one-tailed right this mean you'll reject the null hypothesis to high values of X²

X^2_{k-1;1-\alpha }= X^2_{4;0.95}= 9.488

Decision rule using the critical value approach:

If X^2_{H_0} ≥ 9.488, reject the null hypothesis

If X^2_{H_0} < 9.488, don't reject the null hypothesis

X^2_{H_0}= \frac{(193-360)^2}{360} + \frac{(384-260)^2}{260} + \frac{(170-210)^2}{210} + \frac{(90-90)^2}{90} + \frac{(163-80)^2}{80} = 230.34

The value of the statistic under the null hypothesis is greater than the critical value, so the decision is to reject the null hypothesis.

Using a 5% level of significance, there is significant evidence to conclude that the current market greatly differs from the preference distribution of 1990.

5 0
3 years ago
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