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3 years ago

5. You encounter a material that is white, powdery, with a low melting point, and no luster.

Chemistry

1 answer:

Jet001 [13]3 years ago

3 0

Non metal

Metals have high melting points, are not brittle or powdery, luster and are not white in colour

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How many moles are contained in a 4.67-l sample of gas at 30°c and 199 kpa?

ohaa [14]

Pv=nRT
where,p=199, R(constant)=8.314, V=4.67 T=30C=293K
n=pv/RT=0.38 moles

4 0

4 years ago

Read 2 more answers

A recipe for bread states that the dough must bake for 40 minutes at a temperature of 190°C. The oven you are using has temperat

Mila [183]

Answer:

374°F

463.15K

Explanation:

This particular Question wants to test knowledge on the conversion of the units of temperature from celsius degree to degree Fahrenheit. Also, the conversion of degree celsius to kelvin.

The value given which is 190 degree celsius can be converted into degree Fahrenheit using the formula below;

(x°C × 9/5 ) + 32.

Therefore, x = 190°C =( 190°°C × 9/5) + 32 = 374°F.

The conversion of degree celsius to kelvin is given below as;

x°C + 273.15 .

Therefore, x = 190°C = 190°C + 273.15 = 463.15K.

Therefore, the temperature needed to bake at Fahrenheit and kelvin are 374°F and 463.15K respectively.

8 0

4 years ago

Oxygen decays to form nitrogen. 15 8 O → 15 7 N + 0 1 e This type of nuclear decay is called

Natasha2012 [34]

The type of nuclear decay in which Oxygen decays to form nitrogen is beta plus decay.

<h3>What is a beta plus decay?</h3>

A beta plus decay is a type of decay in which a proton in an element disintegrates to produce a neutron resulting in a decrease in the atomic number of the radioactive element.

In the given equation below:

$^{15}_{7}O \rightarrow ^{15}_{7}N + ^{0}_{1}e$

Oxygen decays to form nitrogen due to a decrease in atomic number.

This is an example of beta plus decay.

In conclusion, oxygen decays to form nitrogen beta plus decay.

Learn more about beta plus decay at: brainly.com/question/12448836

#SPJ1

5 0

3 years ago

Given a certain chemical reaction the change of enthalpy is -91.8 kj/mol. The change of entropy is -198 j/k per mole. At what te

shusha [124]

Explanation:

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7 0

3 years ago

4. A 0.100 M solution of NaOH is used to titrate an HCl solution of unknown concentration. To neutralize the solution, an averag

PtichkaEL [24]

Answer:

C. 0.191 M

Explanation:

Our goal for this question, is to calculate the concentration of the HCl solution. For this, in the experiment, a solution of NaOH was used to find the moles of HCl. Therefore, our first step is to know the reaction between HCl and NaOH:

$HCl~+~NaOH~->~NaCl~+~H_2O$

The "titrant" in this case is the NaOH solution. If we know the concentration of NaOH (0.100M) and the volume of NaOH (38.2 mL=0.0382 L), we can calculate the moles using the molarity equation:

$M=\frac{mol}{L}$

$0.100~M=\frac{mol}{0.0382~L}$

$mol=0.100~M*0.0382~L=0.0382~mol~of~NaOH$

Now, in the reaction, we have a 1:1 molar ratio between HCl and NaOH (1 mol of HCl is consumed for each mole of NaOH added). Therefore we will have the same amount of moles of HCl in the solution:

$0.0382~mol~of~NaOH\frac{1~mol~HCl}{1~mol~NaOH}=0.0382~mol~HCl$

If we want to calculate the molarity of the HCl solution we have to divide by the litters of HCl used in the experiment (20 mL= 0.02 L):

$\frac{0.0382~mol~HCl}{0.02~L}~=~0.191~M$

The concentration of the HCl solution is 0.191 M

I hope it helps!

8 0

3 years ago