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My name is Ann [436]
3 years ago
9

How many moles are contained in a 4.67-l sample of gas at 30°c and 199 kpa?

Chemistry
2 answers:
dezoksy [38]3 years ago
8 0

Answer is: 0.37 moles are contained.

p = 199 kPa; pressure of the gas.

T = 30°C = 303.15 K; temperature of the gas.

V = 4.67 L; volume of the gas.

R = 8.314 J/K·mol; gas constant..

Use ideal gas law: p·V = n·R·T.

n = p · V ÷ (R · T).

n = 199 kPa · 4.67 L ÷ (8.314 J/K· mol · 303.15 K).

n = 0.37 mol; amount of the gas.

ohaa [14]3 years ago
4 0
Pv=nRT
where,p=199, R(constant)=8.314, V=4.67 T=30C=293K
n=pv/RT=0.38 moles
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Answer:

  • <u>Option A. 450.00</u>

Explanation:

<u>1) Data:</u>

a) m = 18 kg

b) T₁ = 285 K

c) T₂ = 318 K

d) Q = 267.3 kJ

e) S = ?

<u>2) Principles and equations</u>

The specific heat of a substance is the amount of heat energy absorbed to increase the temperature of certain amount (gram, kg, or moles, depending on the definition or units) of the substance in 1 ° C or 1 K.

The mathematical relation between the specific heat and the heat energy absorbed is:

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Where,

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<u>3) Solution:</u>

<u>a) Substitute the data into the equation:</u>

  • 267.3 kJ = 18 kg × S × (318 K - 285 K)

<u>b) Solve for S and compute:</u>

  • S = 267.3 kJ / (18 kg × 33 K) = 0.45 kJ / (Kg . K)

The options have not units, but I notice that the first answer is 1,000 times the answer I obtained, so I will make a conversion of units.

<u>c) Convert to J /( kg . k):</u>

  • 0.45 kJ / (Kg . K) × 1,000 J / kJ = 450 J / (kg . K)

Now we can see that the option A is is the answer, assuming the units.

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